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nikitadnepr [17]
3 years ago
12

What is the least common multiple of the numbers 5, 25, and 15? A. 25 B. 50 C. 75 D. 100 E. 125

Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

I would choose c.75 because when I divided 75 by 5 and 15 and 25, I got a whole number for all of them.

makvit [3.9K]3 years ago
6 0

<em><u>Answer: ⇒ C. 75</u></em>

<u><em>"The least common multiple of 5, 25, and 15 is 75."</em></u>

_______________________________________________________

Step-by-step explanation:

Factors of 5: 1, 5

Factors of 25: 1, 5, 25

Factors of 15: 1, 3,5,15

5*1=5

3*5=15

5²=5*5=25

5²*3=5*5=25*3=75

75 it's the correct answer.

___________________________________________________

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

____________________________________________________________

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horsena [70]
No it does not. :) hope this helps
7 0
3 years ago
Read 2 more answers
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
Kirsten has 9 syrup containers from a local cafe. There are 6 milliliters of syrup per container.
ololo11 [35]

Answer: 54 mL

Step-by-step explanation:

Simply do 9(number of containers)*6(Syrup per container) to get 54 mL of syrup.

<em>Hope it helps <3</em>

3 0
3 years ago
A muffin recipe, which yields 12 muffins, calls for 2/3 cup of milk for every 1 3/4 cups of flour. The same recipe calls for 1/4
djyliett [7]

Answer:

4\dfrac{3}{8} cups of flour

Step-by-step explanation:

A muffin recipe, which yields 12 muffins, calls for 2/3 cup of milk for every 1 3/4 cups of flour.

Then this recipe, which yields one muffin, calls for

\dfrac{2}{3}:12=\dfrac{2}{3}\cdot \dfrac{1}{12}=\dfrac{1}{18}

cup of milk for every

1\dfrac{3}{4}:12=\dfrac{7}{4}\cdot \dfrac{1}{12}=\dfrac{7}{48}

cups of flour.

Thus,

this recipe, which yields a batch of 30 muffins, calls for

\dfrac{1}{18}\cdot 30=\dfrac{5}{3}=1\dfrac{2}{3}

cups of milk for every

\dfrac{7}{48}\cdot 30=\dfrac{210}{48}=\dfrac{35}{8}=4\dfrac{3}{8}

cups of flour.

4 0
3 years ago
Please help me with algebra part B and C. attachment below. Will mark as brainslist. 25 points.
miv72 [106K]

Answer:

C. (-7x+60)(x+4)

Step-by-step explanation:

Consider the expression -7x^2+32x+240.

First, note that

a=-7\\ \\b=32\\ \\c=240

Find the discriminant

D=b^2-4ac=32^2-4\cdot (-7)\cdot 240=1,024+6,720=7,744\\ \\\sqrt{D}=\sqrt{7,744}=88

Now,

x_1=\dfrac{-b+\sqrt{D}}{2a}=\dfrac{-32+88}{2\cdot (-7)}=-4\\ \\x_2=\dfrac{-b-\sqrt{D}}{2a}=\dfrac{-32-88}{2\cdot (-7)}=\dfrac{60}{7}

Write the factored form:

-7x^2+32x+240=-7(x-(-4))\left(x-\dfrac{60}{7}\right)=(x+4)(-7x+60)

8 0
3 years ago
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