To find the distance between two points on a coordinate plane, we can apply the distance formula.
√((2 - 0)² + (3 - 6)²)
√(4 + 9)
√13
<h3>The distance between the two points is √13.</h3>
Which linear equation describes the line passing through point (10,3) and has a y-intercept at (0,-1)?
1 answer:
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Answer: x = 5π/6
Explanation:
1) Given function:
2) x-intercept are the roots of the function, i.e. the solution to y = 0
3) to find when y = 0, you can either solve the equation or look at the graph.
4) Solving the equation you get:
y = 0 ⇒ tan(x - 5π/6) = 0 ⇒ x - 5π/6 = arctan(0)
arctan(0) is the angle whose tangent is zero,so this is 0
⇒ x - 5π/6 = 0 ⇒ x = 5π/6.
Then, one example of an x-intercept is x = 5π/6, which means that when x = 5π/6, the value of the function is 0.
Since, the tangent function is a periodic function, there are infinite x-intecepts, that is why the questions asks for one example and not all the values.
You can verify by replacing the value x = 5π/6 in the given function:
y = tan (5π/6 - 5π/6) = tan(0) = 0.
Explanation:
1) Given function:
2) x-intercept are the roots of the function, i.e. the solution to y = 0
3) to find when y = 0, you can either solve the equation or look at the graph.
4) Solving the equation you get:
y = 0 ⇒ tan(x - 5π/6) = 0 ⇒ x - 5π/6 = arctan(0)
arctan(0) is the angle whose tangent is zero,so this is 0
⇒ x - 5π/6 = 0 ⇒ x = 5π/6.
Then, one example of an x-intercept is x = 5π/6, which means that when x = 5π/6, the value of the function is 0.
Since, the tangent function is a periodic function, there are infinite x-intecepts, that is why the questions asks for one example and not all the values.
You can verify by replacing the value x = 5π/6 in the given function:
y = tan (5π/6 - 5π/6) = tan(0) = 0.