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notsponge [240]
3 years ago
7

Help me with 22 and 23

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

22.

pythagorean theorem says legs a and b and hypotenuse c of a right triangle are related via the equation c²=a²+b². in other words, adding the sum of the squares of the legs get you the square of the hypotenuse

if the hypotenuse is 4 meters long, c = 4.

if one leg is 3 meters long, we can choose either a or b to be 3. it does not really matter. let us choose a = 3. now we have to find b.

if we have c²=a²+b², we can solve for b.

subtract a² both sides to get c²-a²=b², and then square root both sides to get

b = √(c²-a²)

plugging in our info we get

b = √(4²-3²) = √(16 -9) = √7

so the answer is √7 meters for 22


23

two triangles are similar, then the proportion of their sides are the same. the propotion between the smaller triangles' hypotenuse and 2cm leg is 5cm/3cm.

notice how the bigger triangle just have a doubled hypotenuse. therefore, the bigger triangle's x and y are just the corresponding smaller triangle values doubled.

x = 6 and y = 8

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The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
Rzqust [24]

The first term of the arithmetic progression exists at 10 and the common difference is 2.

<h3>How to estimate the common difference of an arithmetic progression?</h3>

let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.

We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula

The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.

9th term = 50

a + 8d = 50 ...............(1)

12th term = 65

a + 11d = 65 ...............(2)

subtract them, (2) - (1), we get

3d = 15

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If a + 8d = 50 then substitute the value of d = 5, we get

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a + 40 = 50

a = 50 - 40

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4 0
2 years ago
In figure find the area of the red part.​
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Step-by-step explanation:

Given : A rectangle 4 x 8 , a semicircle

Diagonal intersecting semicircle  

To Find :Area of red part

<h3>Solution:</h3>

Angle AC make AB   α = ∠BAC

tan α = BC/AB = 4/8 = 1/2

=> α = 26.565°

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EC = EF = 4

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=>  ∠AEF =  2α - 45°  = 8.13°

in Left side area  between square  and circle is split in 2 Equal parts

(1/2) area - area AFG = area of Red part

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= 3.4336 sq unit

half  =  1.7168 sq unit  

Now find area AFG = area ΔAEF - sector EGF

area ΔAEF  

AE = 4√2  , EF = 4    angle = 8.13°

area ΔAEF   = (1/2) 4√2 * 4 sin 8.13° = 1.6 sq unit

area  sector EGF  = (8.13/360)π4² = 1.135  sq unit

area AFG  = 1.6 - 1.135  = 0.465 sq unit

Area of Red part = 1.7168 - 0.465 sq unit

= 1.2518 sq unit

= 1.252  sq unit

= 1.25 sq unit.

Hope this helps!!

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3 years ago
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