Question

Oneta writes an algebraic expression with three terms. The y-term has a coefficient of -3, and the x-term has a coefficient of 1. The expression does not have a constant term. Which expression could she have written?
x - y2 - 3y
x - 3y + 6
x + 3y2 + 3y
x + 3y + 7

Answer 1

Answer:  The correct option is

(A) $x-y^2-3y.$

Step-by-step explanation:  Given that Oneta writes an algebraic expression with three terms in which the y-term has a coefficient of -3, the x-term has a coefficient of 1 and there is n constant term.

We are to select the correct expression she could have written.

The coefficient of y term is -3, so one of the terms in the expression is -3y.

The coefficient of x term is 1, so second term is x.

And there is no constant term. Since options (B) and (D) contains constant terms, so they cannot be correct.

Also, the coefficient of y in option (C) is 3, not -3. So, option (C) is also not correct.

The only expression that matches with the given conditions is $x-y^2-3y,$ where the coefficient of y term is -3, the coefficient of x term is 1 and there is no constant term.

Thus, (A) is the correct option.