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lord [1]
3 years ago
7

Mr. kelly uses an expression to represent the perimeter of a square. Rewrite the expression to represent the length of a side of

the square. P=8x+20
Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

Step-by-step explanation:

P = 8x + 20

4*side = 8x + 20

side = (8x + 20)/4

= 8x/4 + 20/4

side = 2x + 5

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tekilochka [14]
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2 years ago
An account in which money cannot be withdrawn until the maturity date is considered what type of account?
aivan3 [116]

Answer:

Certificate of deposit

Step-by-step explanation:

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What is 43.6925 rounded to the nearest thousands place
k0ka [10]

Answer:

43.693

Step-by-step explanation:

8 0
3 years ago
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
Read 2 more answers
Triangle CDE is an isosceles triangle with angle d congruent to angle E if CD= 4x+9, DE= 7x-5, CE= 16x-27, find x and the measur
Montano1993 [528]
ANSWER

x = 3
CD= 21 \: units
DE= 16 \: units

CE= 21 \: units



EXPLANATION

It was given that ∆CDE is an isosceles triangle.

The length of the sides are given in terms of x as follows.

CD=4x+9


DE=7x-5


CE=16x-27



It was also given that, angle D is congruent to angle E.


This implies that, side CD and CE are equal.


Thus,

|CD|  =  |CE|
In terms of x, we have;

4x + 9 = 16x - 27


We group like terms to get,

16x - 4x = 9 + 27

12x = 36

Divide both sides by 12 to get,

x =  \frac{36}{12}

\therefore \: x = 3


The length of the sides are;

CD=4(3)+9 = 21 \: units

DE=7(3)-5 = 16 \: units


CE=16(3)-27 = 21 \: units
3 0
3 years ago
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