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mafiozo [28]
3 years ago
8

Someone help pls and thanks

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0
C I am soooo sorry if I’m wrong
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Ruben bought 6 comic books for $21dollar , 21. Each comic book was the same price.
musickatia [10]

Answer:

3.5 dollars

Step-by-step explanation:

The price of one comic book is 3.5.

I got this by dividing 21 and 6  

6 0
3 years ago
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Your beginning balance on your lunch account is $55. You buy lunch for 1.75 everyday and sometimes buy a snack for $0.85 after 2
Agata [3.3K]
Multiply 1.75 with 25 because you bought snacks everyday and then you’re left with 11.25

Now subtract .20 because you were left with that on day 26 and you get 11.05

Lastly you divide 11.05 with .85 to see how many snacks you bought

ANSWER IS 13 snacks
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3 years ago
The sum of 18 and a number
Pani-rosa [81]
The sum of 18 and 3 is 21
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3 years ago
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Find the distance from the origin to the graph of 7x+9y+11=0
Cerrena [4.2K]
One way to do it is with calculus. The distance between any point (x,y)=\left(x,-\dfrac{7x+11}9\right) on the line to the origin is given by

d(x)=\sqrt{x^2+\left(-\dfrac{7x+11}9\right)^2}=\dfrac{\sqrt{130x^2+154x+121}}9

Now, both d(x) and d(x)^2 attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

d(x)^2=\dfrac{130x^2+154x+121}{81}\implies\dfrac{\mathrm dd(x)^2}{\mathrm dx}=\dfrac{260}{81}x+\dfrac{154}{81}

Solving for (d(x)^2)'=0, you find a critical point of x=-\dfrac{77}{130}.

Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.

You have

\dfrac{\mathrm d^2d(x)^2}{\mathrm dx^2}=\dfrac{260}{81}>0

so indeed, a minimum occurs at x=-\dfrac{77}{130}.

The minimum distance is then

d\left(-\dfrac{77}{130}\right)=\dfrac{11}{\sqrt{130}}
4 0
4 years ago
What do you have to do? Business insurance for 6 months $2,300. Give an answer! I will give you 100 points
tankabanditka [31]

Answer:

im sorry but what is the actual question are you suppose to find a monthly cost or????


3 0
3 years ago
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