Someone help pls and thanks

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

4 0

C I am soooo sorry if I’m wrong

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an Carlos County Health Department reported 17 new cases of tuberculosis in the first half of 2001 and 18 additional cases durin

Tpy6a [65]

Answer:

San Carlos County

Step-by-step explanation:

a) Data and Calculations:

Number of cases of tuberculosis reported in the first half of 2001 = 17

Number of cases of tuberculosis reported in the second half = 18

Total number of cases reported = 35 (17 + 18)

Population of the county at the beginning of 2001 = 204,500

Population of the county at the end of the year = 215,000

Average population for the year = 209,750 (204,500 + 215,000)/2

Therefore, the incidence rate of tuberculosis in the county = 35/209,750 * 100

= 0.000167

b) Since the incidence rate is <1, it suggests that the population of San Carlos County is at a very reduced risk of exposure to tuberculosis. This means that only 1 in 6,000 (209,750/35) people are exposed to the disease in the county.

5 0

3 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$