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Softa [21]
3 years ago
15

Round to the underlined place​

Mathematics
2 answers:
DENIUS [597]3 years ago
5 0

Answer:

i think it would be 75.40

Step-by-step explanation:

The 6 would bring the 3 up one.

Ad libitum [116K]3 years ago
4 0

Answer:

75.36

Step-by-step explanation:

The underlined area is the hundredths place, also known as two decimal places to the right. Hope this helps!

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Please I need help on this
vampirchik [111]

Answer:

53.13

Step-by-step explanation:

To find the measure of an angle use an inverse trig function.

Sin A = \frac{4}{5} so you can take the inverse to find A sin^{-1}\frac{4}{5} = A.

Use a calculator to calculate the value.

A = 53.13

4 0
3 years ago
What is the range of the function<br> f(x) = (x - 1)? when the domain is {-5, 0,5}?
Nimfa-mama [501]

Answer:

f(x) = (x - 1)2

f(x) = 2x - 2

let x = -5, f(x) = -12

let x = 0, f(x) = -2

let x = 5, f(x) = 8

range is {-12, -2, 8}

7 0
2 years ago
Paul spent $13 on writing utensils. Pens cost $3 each and pencils cost $1 each. If he bought a total of 7, how many of each did
dem82 [27]
The answer is 3 pens and 4 pencils. Hope this helps
3 0
2 years ago
Read 2 more answers
48÷479×390÷38789946=
ankoles [38]

correct answer is 0.0000010075

7 0
2 years ago
Read 2 more answers
A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
2 years ago
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