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NeTakaya
3 years ago
12

WILL GIVE BRAINLIESTFind the scale factor​

Mathematics
2 answers:
Sloan [31]3 years ago
7 0
Please I’m in 5th grade I tried but it’s too hard but please mark me Brainlyest
lord [1]3 years ago
4 0

Answer:

Your scale factor would be 2

Step-by-step explanation:

I really hope this helps! :)

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A company manufactures electronics components that each month weigh from 29.5 g to 30.5 g inclusive which of the following inequ
mars1129 [50]

Answer:

The second one represents x = 1

The forth one represents x = 1

They both are correct as they both represent x = 1 and greater than 0.5 minus -1 will equal 30-0.5 it is telling you that when we minus 1 from 30 it (x) cannot be greater than 0.5

Step-by-step explanation:

8 0
3 years ago
The number of words Latisha can text, y,
lyudmila [28]

Answer for A it’s 24

6 0
2 years ago
Find the distance between the coordinates (0, 4) and (10,4) and write the result in the empty box.
barxatty [35]

The distance between the coordinates (0, 4) and (10,4) is 10

Step-by-step explanation:

We need to find the distance between the coordinates (0, 4) and (10,4)

The formula used to find distance is:

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where

x_1=0, y_1=4, x_2=10,y_2=4

Putting values:

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(10-0)^2+(4-4)^2}\\Distance=\sqrt{(10)^2+(0)^2}\\Distance=\sqrt{(10)^2}\\Distance=10

So, The distance between the coordinates (0, 4) and (10,4) is 10

Keywords: Distance between coordinates

Learn more about Distance between coordinates at:

  • brainly.com/question/10364988
  • brainly.com/question/11638377
  • brainly.com/question/3969582

#learnwithBrainly

5 0
3 years ago
2•2 divided by 2+2-2=
dsp73
The answer would be 2.
7 0
3 years ago
Read 2 more answers
What are the vertical asymptotes of the function f(x) =5x+5/x2 + x-2
katen-ka-za [31]

let's recall that the vertical asymptotes for a rational expression occur when the denominator is at 0, so let's zero out this one and check.

\bf \cfrac{5x+5}{x^2+x-2}\qquad \stackrel{\textit{zeroing out the denominator}~\hfill }{x^2+x-2=0\implies (x+2)(x-1)=0}\implies \stackrel{\textit{vertical asymptotes}}{ \begin{cases} x=-2\\ x=1 \end{cases}}

5 0
3 years ago
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