Given :
A sailor is 30 m above the water in the crow's nest on a sailboat.
The sailor encounters an orca surface at an angle of depression of 15 degrees.
The crows nest is 20 m horizontally from the bow (front) of the boat.
To Find :
How far in front of the boat is the orca.
Solution :
Let, distance of boat front from the crow's nest is x.
So,
Hence, this is the required solution.
Answer:
114.4
Step-by-step explanation:
421.2
-305.2
114.4
Answer:
a. <u><em>14:45pm</em></u> (It's really easy to convert to a 24-hour clock time, all you need to do is add 12 hours onto the hour. Eg. 2 + 12 = 14 so it will be 14:45.pm
b. The length of time between 11:45am and 2:45pm is <em><u>3 hours.</u></em>
I don't know what c is sorry.
Hope that helps. x
Answer:
and 
Step-by-step explanation:
Assume that the terminal side of thetaθ passes through the point (−12,5).
In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.
Using Pythagoras theorem:
Taking square root on both sides.
In a right angled triangle
In second quadrant only sine and cosecant are positive.
and
4³/₄ × 1¹/₂
¹⁹/₄ × ³/₂
⁵⁷/₈
7¹/₈
