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klasskru [66]
3 years ago
9

Brainlieat.

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0

So for this, we will be doing a system of equations, with one equation representing the total invested and the other equation representing the total gained from the investments. But first, we have to do calculations:

firstly, to represent a percentage gain (in this case 12% gain) you are to add 0.12 (12% in decimal form) to 1 to get 1.12. <em>Keep 1.12 in mind, as it will be used for the equations.</em>

Next, to represent a percentage loss (in this case 11%), you are to subtract 0.11 (11% in decimal form) from 1 to get 0.89. <em>Keep 0.89 in mind, as it will be used in the equations.</em>

Next, we need to find the total amount of money after the investments. To do this, add 21,000 and 1,715 together to get 22,715. <u>$22,715 is the total amount of money gained in 1 year.</u>

Now that we have all of our information, we can form our equations as such:

  • Let x = $ invested into the account with 12% gain and y = $ invested into the account with 11% loss

x+y=21000\\1.12x+0.89y=22715

Now with these system of equations, I will be using the substitution method. So firstly, with the first equation subtract x on both sides of that equation:

y=21000-x\\1.12x+0.89y=22715

Now that we know that y = 21000 - x, replace y for (21000 - x) in the second equation and solve for x as such:

1.12x+0.89(21000-x)=22715\\1.12x+18690-0.89x=22715\\0.23x+18690=22715\\0.23x=4025\\x=17500

Now that we have the value of x, substitute it into either equation to solve for y:

17500+y=21000\\y=3500\\\\1.12(17500)+0.89y=22715\\19600+0.89y=22715\\0.89y=3115\\y=3500

<u>In short, $17500 was invested into the account that gained 12% and $3500 was invested into the account that had lossed 11%.</u>

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An altitude of a right triangle to its hypotenuse divides this hypotenuse into two segments that measure 9cm, and 16cm. What are
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Answer:

Step-by-step explanation:

Let a be the length of the altitude, then from the given triangles, applying the basic proportionality theorem,  we get

\frac{BD}{AD}=\frac{DC}{BD}

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⇒(BD)^2=9{\times}16

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Problem 5

The function is continuous for the given domain x \ge 6

This is because y = (-5/6)x+5 is itself continuous, and any interval subset of this function is also continuous. We can plug in any real number that is equal to 6 or larger, and get some y output. If we plugged in x = 6, then we'd get

y = (-5/6)x+5

y = (-5/6)*6 + 5

y = -5+5

y = 0

This is the largest y value possible. Why? Because y = (-5/6)x+5 has a negative slope, so the graph is going downhill as you read it from left to right. As x gets bigger, y gets smaller. The smallest x value allowed in the domain produces the largest y value in the range. There is no smallest y value as the y values keep going down forever.

The range is therefore y \le 0

In interval notation, you can write the range as (-\infty, 0]. The square bracket indicates "include this endpoint as part of the range".

======================================================

Problem 6

The function is discrete for this given domain. The domain itself is a discrete list of values. We cannot plug in values between say 0 and 2. We can only substitute one of those values from the list given. Consequently, the y values will also be a list, and not an interval like problem 5 had.

-----------

If you plugged in x = -4, then you should get...

y = (-1/2)*(-4)+2

y = 2+2

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So the input x = -4 lead the output y = 4

Repeat for x = -2

y = (-1/2)x+2

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