A business shipped 106 packages one day. Customers are charged 4.50 for each standard delivery and 7.50 for each express delivery. Total shipping charges for the day were $600.00. How many of each kind of package were shipped?

Answer:

The business shipped 65 standard delivery packages and 41 express delivery packages.

Step-by-step explanation:

Since the business shipped 106 packages one day you can say that:

x+y=106, where:

x is the number of standard delivery packages

y is the number of express delivery packages

Also, you can say that the result of multiplying the price per each type of package for its amount and adding those would be equal to the total shipping charges for the day, which is:

4.50x+7.50y=600

So, you have the following equations:

x+y=106 (1)

4.50x+7.50y=600 (2)

Now, you can solve for x in (1):

x=106-y (3)

Then, you can replace (3) in (2) and solve for y:

4.50(106-y)+7.50y=600

477-4.50y+7.50y=600

3y=600-477

3y=123

y=123/3

y=41

Finally, you can replace the value of y in (3) to be able to find the value of x:

x=106-41

x=65

According to this, the answer is that the business shipped 65 standard delivery packages and 41 express delivery packages.

3 0

3 years ago

What are the real square roots of .0625

Andreas93 [3]

Assuming you can't simply put the number inside a calculator: write the number as a fraction:

$0.0625 = \frac{625}{10000}$

Find the prime factorization both numerator and denominator:

$\frac{625}{10000} = \frac{5^4}{2^45^4}$

The square root halves the exponents, so the number becomes

$\sqrt{\frac{625}{10000}} = \frac{5^2}{2^25^2} = \frac{25}{100} = 0.25$

5 0

3 years ago

Question number 7 only

Mama L [17]

Answer:

the answer is (4)

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3 years ago