A. How many different selections are possible?
B. What is the probability of winning?
C. If you win, what is your net profit?
D. Find the expected value
Answer :
A. sequence of three digits (from 0 to 9). so 10 numbers.
We know 3 lottery games. So possible selections = 10^3 = 1000
B. Probability of winning = one outcome / total outcomes
P( winning) =
= 0.001
c. Net profit = winning amount - paid amount
= 384.13 - 1.33 = $382.8
D. expected value
E(x) = net profit * winning probability - paid amount * lost probability
E(x) = 382.8 * 0.001 - 1.33 * 0.999 = -0.95
you expect to lose 95 cents per ticket.
Answer:
a. y = 250 (0.4)^x
b. 0.066
Step-by-step explanation:
The equation can be modeled as a geometric sequence, where the first term is 100 and the common ratio is 0.4.
y = 100 (0.4)^(x − 1)
This can also be simplified to:
y = 250 (0.4)^x
When x = 9:
y = 250 (0.4)^9
y = 0.066
Answer:
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Step-by-step explanation:
The value of the quantity after 99 months is 5228.58.
Given that, an initial value = 5900, rate of decay = 0.85% and time period = 7 years.
<h3>What is the exponential decay?</h3>
The quantity decreases slowly after which the rate of change and the rate of growth decreases over a period of time rapidly. This decrease in growth is calculated by using the exponential decay formula.
The exponential decay formula formula is 
Here, the value 
= 5900×
= 5900×0.8862
= 5228.58
Therefore, the value of the quantity after 99 months is 5228.58.
Learn more about the exponential decay here:
brainly.com/question/13674608.
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Pretty sure the equation is 4x-3=63 to solve for X.
1. Add three on both sides to get 4x=63
2. Then divide 4 on both sides, getting x=15