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Zina [86]
3 years ago
8

2x+4=8 what would the equation be and what does x equal

Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

  x = 2

Step-by-step explanation:

The equation shown is a perfectly good equation.

___

Look at what is being done to the variable. It is multiplied by 2, and 4 is added to the product.

To find the value of the variable, we reverse these operations, in reverse order. We undo the addition by adding the opposite of 4 (to both sides of the equation).

  2x +4 -4 = 8 -4

  2x = 4 . . . . . simplify

We undo the multiplication by multiplying by the inverse value, 1/2 (to both sides of the equation).

  (1/2)(2x) = (1/2)(4)

  x = 2 . . . . . simplify

_____

The rules of equations are pretty simple: <em>whatever you do to one side, you must also do to the other side</em>.

_____

<em>Comment on this equation</em>

You may notice that all of the numbers in this equation are divisible by 2. Another way to solve it is to start by dividing (both sides!) by 2:

  x + 2 = 4

Now, you have a 2nd-grade problem in addition facts: what added to 2 gives 4? Since you know your addition facts, you know the answer is 2. In algebra, we solve this by subtracting 2 (from both sides!).

  x = 2

Dafna11 [192]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

2x+4=8

2x=8-4

2x=4

x=4/2

x=2

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Step-by-step explanation:

3x+4=17x-10

Subtract 4 from both sides:

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Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.
eimsori [14]

Answer:

(a) 5^{8}

(b) 3

(c) 27

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Step-by-step explanation:

We need simplify the given expressions.

(a)

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Using the properties of exponents we get

(5^4)(5^4)           [\because (a^m)^n=a^{mn}]

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5^{8}

(b)

Consider the given expression is

(9^{\frac{1}{3}})(3^{\frac{1}{3}})

((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})

Using the properties of exponents we get

(3^{\frac{2}{3}})(3^{\frac{1}{3}})           [\because (a^m)^n=a^{mn}]

3^{\frac{2}{3}+\frac{1}{3}}                 [\because a^ma^n=a^{m+n}]

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3

(c)

Consider the given expression is

(\dfrac{1}{3})^{-3}

Using the properties of exponents we get

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(d)

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Using the properties of exponents we get

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6^{-1}

\dfrac{1}{6^{1}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{1}{6}  

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3 years ago
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