Question

A complete description of simple harmonic motion must take into account several physical quantities and various mathematical relations among them. This information is needed to solve oscillation problems of this type.The position of a 60 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds.Part ADetermine the velocity at t=0.40s.Express your answer in meters per second to two significant figures.

Answer 1

Answer:

Velocity will be -0.0139 m/sec

Explanation:

We have given mass m = 60 gram = 0.06 kg

Equation of displacement $x(t)=2cm\ cos(10t)=0.02cos(10t)$

We have to find the velocity at t = 0.4 sec

We know that velocity is given by

$v(t)=\frac{dx(t)}{dt}$

So velocity $v(t)=\frac{dx(0.02cos(10t))}{dt}=-0.02\times 10sin(10t)=-0.2sin(10t)$

At t = 0.4 sec

$v(t)=-0.2sin(10\times 0.4)=-0.0139m/sec$