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worty [1.4K]
3 years ago
13

The potential energy of an object attached to a spring is 2.60 J at a location where the kinetic energy is 1.40 J. If the amplit

ude ???? of the simple harmonic motion is 16.0 cm, calculate the spring constant ???? and the magnitude of the largest force ????spring, max that the object experiences.
????= Nm

????spring, max= N
Physics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant. 

 U = (1/2)kx^2 

 U = (1/2)(5.3)(3.62-2.60)^2 

 U =  2.75706 J

Read more on Brainstorm - httpd://brainstorm/question/7981441#read more

Explanation:

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To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as V_1, the relation with the final volume as

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