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bulgar [2K]
1 year ago
8

what kinds of investigations might have led to our current understanding of matter and energy? why is it important for scientist

s to use the same scientific method and consistent measurement units?
Physics
1 answer:
lana66690 [7]1 year ago
6 0

The kind of investigations might have led to our current understanding of matter and energy is research and measurement.

It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.

<h3>What is matter?</h3>

The matter has volume and space occupied.

When conceivable the researcher endeavors to test his speculations via painstakingly planned and controlled tests that will yield quantitative instead of subjective outcomes.

Thus, the kind of investigations might have led to our current understanding of matter and energy is research and measurement.

It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.

Learn more about matter.

brainly.com/question/4513444

#SPJ1

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The nucleus of a hydrogen atom is a single proton, which has a radius of about 1.2 × 10-15 m. The single electron in a hydrogen
Nutka1998 [239]

Answer: 0.86 × 10^14

Explanation:

Given the following :

Radius of proton = 1.2 × 10-15 m

Radius of hydrogen atom = 5.3 × 10-11 m

Density of proton could be calculated thus:

Mass of proton = 1.67 × 10^-27 kg

Using the formula :

(4/3) × pi × r^3

(4/3) × 3.142 × (1.2 × 10^-15)^3 = 7.24 × 10^-45

Density = mass / volume

Density = (1.67 × 10^-27) / ( 7.24 × 10^-45)

= 0.2306 × 10^18

Density of hydrogen atom:

Mass of hydrogen atom= 1.67 × 10^-27 kg

Using the formula :

(4/3) × pi × r^3

(4/3) × 3.142 × (5.3 × 10^-11)^3 = 6.24 × 10^-31

Density = mass / volume

Density = (1.67 × 10^-27) / ( 6.24 × 10^-31)

= 0.2676 × 10^4

Ratio is thus:

Density of proton / density of hydrogen atom

0.2306 × 10^18 / 0.2676 × 10^4 = 0.8617 × 10^14

6 0
3 years ago
When a man returns to his well-sealed house on a summer day, he finds that the house is at 35°C. He turns on the air conditioner
Paul [167]

Answer:

1353.38 Watt

Explanation:

T₁ = Initial temperature of the house = 35°C

T₂ = Final temperature of the house = 20°C

Δt = Time taken to cool the house = 38 min = 38×60 = 2280 s

m = mass of air in the house = 800 kg

Cv = Specific heat at constant volume = 0.72 kJ/kgK

Cp = Specific heat at constant pressure = 1.0 kJ/kgK

Heat removed

q = mCvΔT

⇒q = 800×720×(35-20)

⇒q = 8640000 J

Average rate of hear removal

Q=\frac{q}{\Delta t}\\\Rightarrow Q=\frac{8640000}{2280}\\\Rightarrow Q=3789.47\ W

COP=\frac{Q}{W}\\\Rightarrow W=\frac{Q}{COP}\\\Rightarrow W=\frac{3789.47}{2.8}\\\Rightarrow W=1353.38\ W

∴ Power drawn by the air conditioner is 1353.38 Watt

6 0
2 years ago
Read 2 more answers
A cannonball is fired horizontally at the same time a ball being dropped from the same height How do the times it takes them to
ipn [44]

Answer:

The cannonball and the ball will both take the same amount of time before they hit the ground.

Explanation:

For a ball fired horizontally from a given height, there is only a vertical acceleration on it towards the ground. This acceleration is equal to the acceleration due to gravity (g = 9.81 m/s^2). A ball dropped from a height will also only experience the same vertical acceleration downwards which is also equal to g = 9.81 m/s^2.

Therefore both the cannonball and the ball will take the same amount of time to hit the ground if they are released/fired from the same height.

3 0
3 years ago
According to Ohm’s law, determine the experimental current for these values in Table A.
mojhsa [17]

Answer:

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1.0

2.5

Explanation:

7 0
3 years ago
The data in the table above show how far
Taya2010 [7]

Answer:c

Explanation: because if you work it in a paper it should like lil wit is straight the numbers are going up by 16

6 0
2 years ago
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