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nevsk [136]
3 years ago
7

Which statement is true about the variability of the distributions

Mathematics
1 answer:
luda_lava [24]3 years ago
6 0
The first one. The interquartile range of typing speeds after the course is greater than the interquartile range of speeds before the course.
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What is the length of AC?<br><br> • 10<br> • 12<br> • 15<br> • 20
Gre4nikov [31]
The answer is 12. sorry if i’m wrong
3 0
3 years ago
Your teacher has 36 carpet squares. She needs to make a new arrangement for the reading carpet. What are all of the different wa
stira [4]

Answer: The number of different ways she could arrange the carpet squares is 36!.

Step-by-step explanation:

We know that , the number of ways to arrange n things = n!

Given that , Your teacher has 36 carpet squares.

i.e. The total number of carpet squares = 36

If she needs to make a new arrangement for the reading carpet.  

Then, the total number of arrangement of carpet squares would be 36!.

Hence , the number of different ways she could arrange the carpet squares is 36!

4 0
3 years ago
The length of a rectangle is 3 times the width. The perimeter is 44 cm. What are the dimensions of the rectangle? Write and solv
ser-zykov [4K]
Here are your equations:
x and 3x
How to set up:
2(x)+ 2(3x) = 44
Simplify:
8x = 44
Divide:
x = 5.5
Plug back in to find values:
Width = 5.5
Length = 16.5

Hope this helps!! :)
5 0
3 years ago
Could some one plz help me with this question
zhuklara [117]

Answer:

A

Step-by-step explanation:

The formula for this type of interest is A=P(1+\frac{r}{n})^{nt}, where A is the total amount, P is the initial investment, x is the interest rate, n is the amount of times that the investment is compounded a year, and t is the amount of years. Plugging in the numbers given, you get:

A=1800(1+\frac{0.025}{2})^{2\cdot 12}=

1800(1.0125)^{24}\approx 2425.23

Now, she invests this into a new account, and you can set up the following equation:

A=2425.23(1+\frac{0.04}{12})^{12\cdot 7}=

2425.23(1.0033333)^{84}\approx 3207.40, or option A.

Hope this helps!

3 0
3 years ago
How many extraneous solutions does the equation below have?
aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S. 

The given equation consisting of  variable , m is

   \frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})

None of the two solution

m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2}), is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0
3 years ago
Read 2 more answers
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