Question

Which complex number from the table multiplied with B from the table will result in the product 159 + 27i?

Answer 1

Answer:

F. -15 + 9i

Step-by-step explanation:

B = (-7 -6i)

Multiply B by F = (-15 + 9i), would give;

B × F = (-7 -6i) × (-15 + 9i)

        = -7 (-15 + 9i) - 6i (-15 + 9i)

       = 105 -63i + 90i - 54($i^{2}$)

But $i^{2}$ = -1, so that:

105 -63i + 90i -54($i^{2}$) = 105 -63i + 90i -54(-1)

                                  = = 105 -63i + 90i + 54

          = 159 + 27i

B × F = 159 + 27i

Thus the required complex number is F (-15 + 9i).