Answer:
she use 750 mL of 0.22% solution and 250 mL of 0.1%
Step-by-step explanation:
given data
salt water solution 1 = 0.1%
salt water solution 2 = 0.22%
1 liter of solution contains salt = 0.13%
solution
we will consider here quantity in liters of the 0.22% solution is = x
so that the quantity of 0.01% solution will be = 1 - x
so amount of salt in the mix will be as here
0.22 % (x) + 0.1 ( 1-x) = 0.13% (1)
solve it we get
x = 0.25
and
1-x will be = ( 1 - 0.25 ) = 0.75
so she use 750 mL of 0.22% solution and 250 mL of 0.1%