A/b ÷ d/c
a/b * c/d
4x/ x² + 5x -6 * x² + 7x + 6/ x² - 11x + 28 factor
4x/ (x+6)(x-1) * (x+6)(x+1)/ (x-7)(x-4) (x+6) cancels out
4x (x+1) / (x-1)(x-7)(x-4)
Answer:
Juan has 32 dimes, 16 nickels and 8 quarters in his coin bank.
Step-by-step explanation:
Since in Juan's coin bank there are nickels (n), dimes (d), and quarters (q), and the number of quarters is one-quarter the number of dimes, and the number of nickels is twice the number of quarters, While the total value of the coins is $ 6.00, to find the number of each type of coin the following calculations must be performed:
Q = 1/4 D
N = 2Q = 1/2 D
D = D
20D + 10N + 5Q = X
20 x 0.10 + 10 x 0.05 + 5 x 0.25 = X
2 + 0.50 + 1.25 = X
3.75 = X
24D + 12N + 6Q = X
24 x 0.10 + 12 x 0.05 + 6 x 0.25 = X
2.40 + 0.60 + 1.50 = X
4.50 = X
32D + 16N + 8Q = X
32 x 0.10 + 16 x 0.05 + 8 x 0.25 = X
3.20 + 0.80 + 2 = X
6 = X
So, Juan has 32 dimes, 16 nickels and 8 quarters in his coin bank.
Answer:
30.67
Step-by-step explanation:
Given the following
Opposite side = x
Adjacent = 17
Angle = 61degrees
Using the SOH CAH TOA identity
tan theta = opp/adj
tan 61 = x/17
x = 17tan61
x = 17(1.8040)
x = 30.67
Hence the value of x is 30.67
Answer:
D: 7B+8N<120
Step-by-step explanation:
The total amount of the bracelets and necklaces is less than $120, so if you add the price of each necklace ($8) and the price of each bracelet ($7), it will be <$120.
Answer:
152 - 4d
Step-by-step explanation:
You had $152
$4 is spent each day
Let d represent the days
Since the money at hand is $152 and $4 is taken away each day then, the algebraic expression which models this situation is
= 152-4d