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Savatey [412]
3 years ago
7

Two solutions of salt water contain 0.1% and 0.22% salt respectively. A lab technician wants to make 1 liter of solution which c

ontains 0.13% salt. How much of each solution should she use? Amount of 0.1% solution = milliliters Amount of 0.22% solution = milliliters
Mathematics
1 answer:
sergey [27]3 years ago
4 0

Answer:

she use 750 mL of 0.22% solution and 250 mL of 0.1%

Step-by-step explanation:

given data

salt water solution 1 =  0.1%

salt water solution 2 = 0.22%

1 liter of solution contains salt = 0.13%  

solution

we will consider here quantity in liters of the  0.22% solution is = x

so that the quantity of 0.01% solution  will be = 1 - x

so amount of salt in the mix will be as here

0.22 % (x) + 0.1 ( 1-x) = 0.13% (1)

solve it we get

x = 0.25

and

1-x will be = ( 1 - 0.25  ) = 0.75

so she use 750 mL of 0.22% solution and 250 mL of 0.1%

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If line q bisects EG at point T, and if ET= 1/3 x and TG= x-2, then find EG
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Step-by-step explanation:

Given that line q bisects EG at T , then

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