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Radda [10]
3 years ago
11

Write an equation in​ point-slope form of the line that passes through the given point and with the given slope m.

Mathematics
1 answer:
miv72 [106K]3 years ago
6 0

the answer is : y - 5 = 6 ( x + 7)

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How many times does 59 go into 6
sveticcg [70]
59 can't go into 9, but if u mean the other way then it is 9.83
4 0
4 years ago
Read 2 more answers
Could someone help what is the variable in “8y3”?
diamong [38]

Answer:

y

Step-by-step explanation:

The variable in 8y^3 is y because a variable is a number that we don't know yet, and that is the only one.

4 0
3 years ago
PROBLEM SOLVING A ski shop sells skis with lengths ranging from 150 centimeters to 220 centimeters. The shop says the length of
grin007 [14]

Answer:

h > 189.66\ cm  or  h< 129.31\ cm

Step-by-step explanation:

Let

h ----> a skier's height in centimeters

we know that

A ski shop sells skis with lengths ranging from 150 centimeters to 220 centimeters

The interval of the skis is -----> [150,220]

The compound inequality that represents the heights (in centimeters) of skiers the shop does not provide skis is

1.16h > 220\ cm ----> inequality A

or

1.16h< 150\ cm ----> inequality B

<em>Solve inequality A</em>

1.16h > 220\ cm

Divide by 1.16 both sides

h > 189.66\ cm

<em>Solve inequality B</em>

1.16h< 150\ cm

Divide by 1.16 both sides

h< 129.31\ cm

therefore

h > 189.66\ cm  or  h< 129.31\ cm

5 0
3 years ago
An SAT coaching company claims it's course can raise SAT scores of high school students (thus, when they take it a second time a
Maru [420]

Answer:

Check the explanation

Step-by-step explanation:

(a) The appropriate test is the matched-pairs test because a student’s score on Try 1 is certainly correlated with his/her score on Try 2. Using the differences, we have xbar =  29 and s = 59.

(b) To test H0: mu=0 vs.  H1 mu > 0, we compute

t = (29-0)/((59/sqrt(427))=10.16

with df = 426. This is certainly significant, with P < 0.0005. Coached students do improve their scores on average

(a) H0: μ1 = μ2 vs. Ha: μ1 > μ2, where μ1 is the mean gain among all coached students and μ2 is the mean gain among uncoached students. H0 and Ha. Using the conservative approach, df = 426 is rounded down to df = 100 in  (t table) and we obtain 0.0025 < P < 0.005. Using software, df = 534.45 and P = 0.004. There is evidence that coached students had a greater average increase.

(b) 8 ± t*(3.0235) where t* equals 2.626 (using df = 100 with (t table) ) or 2.585 (df = 534.45 with software). This gives either 0.06 to 15.94 points, or 0.184 to 15.816 points, respectively.

(c) Increasing one’s score by 0 to 16 points is not likely to make a difference in being granted admission or scholarships from any colleges.

6 0
3 years ago
What are three numbers that are greater than 1/3 but less than 1/2
Gnesinka [82]

Answer:

11/30, 2/5, 7/15

Step-by-step explanation:

5 0
3 years ago
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