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3 years ago

What is the answer to this

Mathematics

1 answer:

astraxan [27]3 years ago

5 0

It is convenient to do part b first, then use that result to do part a.

b. For some pair of points (x1, y1) and (x2, y2), you want to find a point (a, b) such that (a, b) - (x1, y1) = (x2, y2) - (a, b). That is, the differences of coordinates from one end to the center are the same as the differences from the center to the other end.
Adding (a, b) to the above equation gives
2(a, b) - (x1, y1) = (x2, y2)
Adding (x1, y1) then gives
2(a, b) = (x1, y1) + (x2, y2)
Finally, dividing by 2 gives a formula for (a, b):

(a, b) = ((x1, y1) + (x2, y2))/2
The midpoint is the average of the end points.

a. Using the result from part b, the midpoint is
midpoint = ((2, 3) + (6, 7))/2 = (8, 10)/2
midpoint = (4, 5)

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Plz help me people guys xx :)

kaheart [24]

Answer:

48.9

Step-by-step explanation:

Subtract 2 from 99.8 = 97.8

Divide 97.8 by 2 - 48.9

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3 years ago

Jimmy ran at a speed of m miles. how far did he run in t minutes

beks73 [17]

Answer:

(mxt) miles

Step-by-step explanation:

$speed = m \: miles \: per \:minute \\ time \: = t \: minutes \\ speed = \frac{distance}{time} \\ m = \frac{d}{t} \\ m \times t \: = d \\ d = (m \times t)miles$

hope that this is helpful.

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2 years ago

A parallelogram is shown below: Part A: What is the area of the parallelogram? Show your work. (5 points) Part B: How can you de

aksik [14]

Part A) The area of a parallelogram is base × height.

3 × 2/3 = 6/3 = 2

2 feet squared is the area of the whole parallelogram.

Part B) The diagonal of a parallelogram separates it into two congruent triangles.

The area of each triangle will be:

base × height × 1/2

3 × 2/3 × 1/2 = 6/6 = 1

1 foot squared is the area for each triangle.

5 0

3 years ago

Read 2 more answers

Jackie is driving at a speed of 65 miles per hour. Let h represent the number of hours that Jackie drives at this speed. Write a

Dmitriy789 [7]

B is the correct answer

3 0

3 years ago

Help I don’t understand at all

zloy xaker [14]

Answer:

$1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4$

Step-by-step explanation:

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

$2h^2-7h+2h^2-h+6+4h-9h$

$(2h^2+2h^2)+(-7h-h+4h-9h)+(6)$

$4h^2-13h+6$

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

$8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5$

$(8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)$

$7x^3y^2-x^2y+1$

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following ( $a(b+c)=(a)(b)+(a)(c)=ab+ac$ ). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,