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Gennadij [26K]
3 years ago
10

What is the answer to this

Mathematics
1 answer:
astraxan [27]3 years ago
5 0
It is convenient to do part b first, then use that result to do part a.

b. For some pair of points (x1, y1) and (x2, y2), you want to find a point (a, b) such that (a, b) - (x1, y1) = (x2, y2) - (a, b). That is, the differences of coordinates from one end to the center are the same as the differences from the center to the other end.
Adding (a, b) to the above equation gives
  2(a, b) - (x1, y1) = (x2, y2)
Adding (x1, y1) then gives
  2(a, b) = (x1, y1) + (x2, y2)
Finally, dividing by 2 gives a formula for (a, b):

  (a, b) = ((x1, y1) + (x2, y2))/2
The midpoint is the average of the end points.

a. Using the result from part b, the midpoint is
  midpoint = ((2, 3) + (6, 7))/2 = (8, 10)/2
  midpoint = (4, 5)
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A rectangular parking area measuring 5000 ft squared is to be enclosed on three sides using​ chain-link fencing that costs ​$5.5
kaheart [24]

Answer:

Dimensions: 75.3778 ft and 66.3325 ft

Minimum price: $1658.31

Step-by-step explanation:

Let's call the length of the parking area 'x', and the width 'y'.

Then, we can write the following equations:

-> Area of the park:

x * y = 5000

-> Price of the fences:

P = 2*x*5.5 + y*5.5 + y*7

P = 11*x + 12.5*y

From the first equation, we have that y = 5000/x

Using this value in the equation for P, we have:

P = 11*x + 12.5*5000/x = 11*x + 62500/x

To find the minimum of this function, we need to take its derivative and then make it equal to zero:

dP/dx = 11 - 62500/x^2 = 0

x^2 = 65000/11

x = 250/sqrt(11) = 75.3778 ft

This is the x value that gives the minimum cost.

Now, finding y and P, we have:

x*y = 5000

y = 5000/75.3778 = 66.3325

P = 11*x + 62500/x = $1658.31

5 0
4 years ago
Gail can use her 12% employee discount once a week. Last Sunday, she bought a $45 sweater at 1/3 off and used her discount on th
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Statement 1 : Gail bought a $45 sweater at 1/3 off.

<u>Discount in Sweater Purchase:</u>

\frac{1}{3} \; of \; 45 = \frac{1}{3} \times 45 \; = \;\frac{45}{3} =\$15

Statement 2: Gail can use her 12% employee discount once a week and used her discount on the suit priced at $140.

Discount in Suit Purchase:

12\% \; of \; 140 =\frac{12}{100}  \times  140 = 0.12 \times 140 = \$16.8

Conclusion:

<u>Discount in Suit Purchase ($16.8) is greater than Discount in Sweater Purchase ($15)</u>

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