Question

Please can someone help me with this question

Answer 1

Answer:

r = -$\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$  = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

($\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ($\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by  5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5   to the left of (m ^2)  r

6a+r=5m^2)r

Subtract  5m^2)r  from both sides of the equation.

6a+r-5m^2)r=0

Subtract  6a  from both sides of the equation.

r-5m^2)r=-6a

Factor  r out of  r-5m^2)r  

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!