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Aneli [31]
3 years ago
12

as the pressure on a liquid is changed from 70 kpa to 80 kpa, the temperature at which the liquid will boil

Chemistry
1 answer:
anygoal [31]3 years ago
6 0
Answer is: t<span>he boiling point will increase as the external pressure is increases.
</span>The boiling point<span> of a substance is the temperature at which the </span>vapor pressure<span> of the </span>liquid<span> equals the </span>pressure<span> surrounding the liquid, at that temperature</span><span> the liquid changes into a vapor.
</span><span>The boiling point of a liquid dependes upon the surrounding environmental pressure.</span><span>

</span>
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Explanation:

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3 years ago
What is the answer miguel needs to use an electric hot plate to heat a beaker of water. as he starts to plug the hot plate into
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How many litres (L) of oxygen at STP can be obtained from 110 g of potassium chlorate? [R=0.0821 L.atm/K.mol]
lisabon 2012 [21]
Balance the equation first:

2 KClO3 (s) ---> 2 KCl (s) + 3 O2 (g)

Moles of KClO3 =  110 / 122.5 = 0.89

Following the balanced chemical equation:
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So, O2 = (3 / 2) x  0.89

= 1.34 moles

So, Volume at STP = nRT / P

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3 0
4 years ago
A 34.0 g piece of metal is heated to 92.0°C then placed in a beaker of water containing 22.0 g of water at 19.0°C. The temperatu
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Answer:

0.1988 J/g°C

Explanation:

-Qmetal = Qwater

Q = mc∆T

Where;

Q = amount of heat

m = mass of substance

c = specific heat of substance

∆T = change in temperature

Hence;

-{mc∆T} of metal = {mc∆T} of water

From the information provided in this question, For water; m= 22.0g, ∆T = (24°C-19°C), c = 4.18J/g°C.

For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?

Note that, the final temperature of water and the metal = 24°C

-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)

-{34 × c × (-68°C)} = 459.8

-{34 × c × -68} = 459.8

-{-2312c} = 459.8

+2312c = 459.8

c = 459.8/2312

c = 0.1988

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3 years ago
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garik1379 [7]

Answer:

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Step 1: Data given

exact mass of 151.0640

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Molar mass of O = 15.9949 g/mol

Molar mass of N = 14.0031 g/mol

Step 2: Calculate molar mass of C7H5NO3

7*12 + 5*1.00783 + 14.0031 + 3*15.9949 = 151.02695 g/mol

Step 3: Calculate molar mass of C8H9NO2

8*12 + 9*1.00783 + 14.0031 + 2*15.9949 = 151.06337 g/mol

Step 4: Calculate molar mass of C10H17N

10*12 + 17*1.00783 + 14.0031 = 151.13621 g/mol

The molecular formula of X is C8H9NO2

3 0
3 years ago
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