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3 years ago

The value of n in the inequality 3n + 1 < 7 is

Mathematics

1 answer:

aliya0001 [1]3 years ago

8 0

3n + 1 < 7

Solve:

3n < 6

n < 2

The answer is C.

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Fudgin [204]

Answer:

0.2

Step-by-step explanation:

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Write an equivalent expression for each operation.<br> (3 + 2i) + (4 + 5i)<br> Help me plz ASAP

ololo11 [35]

Answer:

The equivalent expression is $7(1+i)$

Step-by-step explanation:

Additional of complex numbers:

When we add complex numbers, we add both it's real parts and imaginary parts.

In this question:

$(3 + 2i) + (4 + 5i) = 3 + 4 + (2+5)i = 7 + 7i = 7(1+i)$

The equivalent expression is $7(1+i)$

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3 years ago

How do you breakdown 5/8+3/10?

FrozenT [24]

Answer:

37/40

you asked how tho, so I included that in the explanation.

Step-by-step explanation:

desimplify:

the LCD is 40

so:

5/8+3/10=25/40+12/40

which is:

37/40

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3 years ago

Which problem solving strategy would be best to solve this problem?

prisoha [69]

Answer:

B) work backwards.

Step-by-step explanation:

Since they are asking for how much money he had at first and they displayed how much he spent without telling the amount of money at the start of the question, this is definitely a backwards question. For working backwards, you will need to do workings the opposite as what they said in the question.

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3 years ago

Need Help !!

Over [174]

$\huge \mathbb{\green{\fbox{\pink{ANSWER}}}}$

$\\ \: \: \implies \: sin^{4} \: \theta + cos^{4} \: \theta \rightarrow \blue{ \frac{1}{2} }$

$\\ \\ \: \large \mathfrak \green{Solution} :$

$\\ \bf \: Given :$

$\\ \sf \: \: \bf sin \: \theta - cos \: \theta = 0$

$\\ \sf \rightarrow \: sin \: \theta = cos \: \theta$

$\\ \sf \rightarrow \: \frac{sin \: \theta} {cos \: \theta} = 1$

$\\ \sf \rightarrow \: tan \: \theta = 1$

$\\ \sf \rightarrow \: tan \: \theta = tan \: 45 \degree$

$\\ \sf \rightarrow \: \theta = 45 \degree$

$\\ \\ \therefore \: sin^{4} \: \theta + cos^{4} \: \theta$

$\\ \sf \rightarrow \: sin^{4} \: 45 \degree + cos^{4} \: 45 \degree$

$\\ \\\sf \rightarrow \: (\frac{1}{ \sqrt{2} } ) ^{4} +(\frac{1}{ \sqrt{2} } ) ^{4}$

$\\ \sf \rightarrow \: ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}} + ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}}$

$\\ \\\sf \rightarrow \: \frac{1}{2} × \frac{1}{2} + \frac{1}{2}× \frac{1}{2}$

$\\ \\ \sf \rightarrow \: \frac{1}{4} + \frac{1}{4}$

$\\ \\ \sf \rightarrow \: {\cancel \frac{2} {4}}$

$\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies \fbox{\pink {\frac{1}{2}}}$

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3 years ago

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