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Anni [7]
3 years ago
6

Whats 34+35 I NEED HELP

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
5 0

Answer:

34

+35

=69

Step-by-step explanation:

Leni [432]3 years ago
3 0

Answer:

34 + 35 = 69

Step-by-step explanation:

Please give me brainliest :)

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The measure of a vertex angle of an isosceles triangle is 120° and the length of a leg is 8 cm. Find the length of a diameter of
Goryan [66]

ANSWER

The length of a Diameter is 3.714

EXPLANATION

The circumscribed triangle is shown in the attachment.

We use the cosine ratio to find the altitude of the isosceles triangle.

\cos(60 \degree)  =  \frac{altitude}{hypotenuse}

\cos(60 \degree)  =  \frac{altitude}{8}

Altitude =8cos(60°)

Altitude=4cm

Let the upper half of the altitude be y cm.

Then the radius of the circle is (y-4)cm

The upper radius meets the tangent at right angles.

From the smaller right triangle,

\sin(60 \degree)  =  \frac{4 - y}{y}

y\sin(60 \degree)  = 4 - y

y\sin(60 \degree)   + y= 4

(\sin(60 \degree)   + 1)y= 4

y=  \frac{4}{\sin(60 \degree)   + 1}

y = 16 - 8 \sqrt{3}

y=1.857

The diameter is 2y

d = 32 - 16 \sqrt{3}

=2(1.875)

The length of a Diameter is 3.714

7 0
3 years ago
Read 2 more answers
Simplify.<br> 3/4 squareroot -48
zepelin [54]

Answer:

3i √3

Step-by-step explanation:

you can't have the square root of a negative number

so we use "i"

6 0
3 years ago
How do I do this help due in tomorrow
Mkey [24]

Answer:

The top one is 135 cm^2

Step-by-step explanation:

To find the area, all you need to do is multiply the 3 different measurements. For the one in the top corner we need to multiply the length by the width by the height. The work is done below for you on that one.

A = l * w * h

A = 15 * 3 * 3

A = 135 cm^2

4 0
4 years ago
2/3 of a class are girls. A) what is the ratio girls to boys in the class? B) what is the ratio boys to girls in the class
tekilochka [14]

a) 2:1

b) 1:2

2/3 are girls so 1/3 are boys

5 0
3 years ago
Please help and show work
Bogdan [553]
The answer should be X= 3.60m
3 0
3 years ago
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