The distance between those two points is 41 and in decimal form to the nearest tenth, that's 6.4
Explanation:
Use the distance formula: √(x2 - x1)² + (y2 - y1)²
Then we plug in our x's and y's:
√(4 - (-1))² + ((-1) - 3)²
Then you simplify:
√(5)² + (-4)² = √25 + 16
√41 (And if you need to, you can put this into decimal form.)
Area = π × r2. Or, when you know the Diameter: A = (π/4) × D2. So A = 6π, which is 18.85. So A = 18.85. And here's the hand.
Equation is
x-6=8
x=8+6
x=14
X equal to 14
The foci need to be equal distances from the center of the eclipse.
See the attached picture. I marked off all the points that were given as choice and from this you can see that that (-5,-4) and (-5,2) are both 3 units away from the center.
The answer is: (-5,-4) and (-5,2)