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3 years ago

What’s the median of these two numbers ? 13 and 13

Mathematics

1 answer:

ale4655 [162]3 years ago

8 0

median: The number that occurs in the middle after arranging in ascending order of magnitude

;13 13

since both appeared in the middle,you add it and divide by 2

13+13/2

26/2

;The median is 13

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Don’t really remember how to do this 8-9

yulyashka [42]

8-9=-1 because it does not stop it goes to the negative number -1

5 0

3 years ago

Pleas help me:)thank you so much<3

malfutka [58]

Step-by-step explanation:

ratios of lengths = 4/3

ratios of area = 16/9

plz mark my answer as brainlist plzzzz vote me also plzzzz .... Hope this helps you ...

6 0

3 years ago

What’s the midpoint of the line segment joining A and B A(2,-5);B(6,1)

IRISSAK [1]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+2}{2}~~,~~\cfrac{1-5}{2} \right)\implies \left( \cfrac{8}{4}~,~\cfrac{-4}{2} \right)\implies (4,-2)$

7 0

3 years ago

Solve: 3c - 15 = 17 - c plsss helpp !! i put 20 pts on this !!

azamat

Answer:

c=8

Step-by-step explanation:

Simplifying

3c + -15 = 17 + -1c

Reorder the terms:

-15 + 3c = 17 + -1c

Solving

-15 + 3c = 17 + -1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'c' to each side of the equation.

-15 + 3c + c = 17 + -1c + c

Combine like terms: 3c + c = 4c

-15 + 4c = 17 + -1c + c

Combine like terms: -1c + c = 0

-15 + 4c = 17 + 0

-15 + 4c = 17

Add '15' to each side of the equation.

-15 + 15 + 4c = 17 + 15

Combine like terms: -15 + 15 = 0

0 + 4c = 17 + 15

4c = 17 + 15

Combine like terms: 17 + 15 = 32

4c = 32

Divide each side by '4'.

c = 8

Simplifying

c = 8

5 0

3 years ago

Read 2 more answers

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago