All categories

3 years ago

Is - 5/12 equivalent to 5/-12

Mathematics

1 answer:

Kamila [148]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

-5/12 is the same as saying 5/-12

Hope this helps! have a nice day! Please consider making me Brainliest

You might be interested in

A coat was listed on sale for 40% off. If the coat normally costs $120, then how much money are you going to save?

Vlada [557]

Answer:

$48

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLEASE HELP LOTS OF POINTS!!!!!!!! TWO QUESTIONS!!!!!!!!!

zubka84 [21]

Answer: Number one would be 3x+2y+-14 and x+y=-4, second one is x=-3, y=7

Step-by-step explanation:

The first one is solved by inputting the x and y in each one and finding which one comes out true, the second on is solved by substitution. to find x you would subtract x in the first equation and make it y=4-x then input that equation in the y in the second equation.

6 0

4 years ago

How do you solve problems like this. Rhonda earned $324.65 delivering newspapers. She promised her sister 0.2 of her earnings fo

ira [324]

Answer:

$64.93

Step-by-step explanation:

All you have to do is multiply the amount of money by the percent (in this case, the decimal of 0.2):

324.65*0.2 = 64.93

8 0

3 years ago

Read 2 more answers

Two students ran exactly 2 1/4 miles. Identify the students. How many quarter miles did each student run?

Anna35 [415]

If both of them ran exaxtly 2 1/4 miles then break it up
2 1/4
4*2 = 8+1 =9
9/4
1/4 +1/4+1/4+1/4 +1/4+1/4+<span>1/4 +1/4+1/4 = 2 1/4
So they ran 9 quarter miles </span>

3 0

3 years ago

Read 2 more answers

X^2 + 4x - 9 = (x + a)^2 + b<br><br> Find the value of a and the value of b

REY [17]

Answer:

Step-by-step explanation:

We have three ways.

$(a+b)^2=a^2+2ab+b^2\qquad(*)$

$\bold{1.}\\\\x^2+4x-9=x^2+2(x)(2)-9=\underbrace{x^2+2(x)(2)+2^2}_{(*)}-2^2-9\\\\=(x+2)^2-4-9=(x+2)^2-13\\\\x^2+4x-9=(x+a)^2+b\\\Downarrow\\(x+2)^2-13=(x+a)^2+b\Rightarrow \boxed{\bold{a=2, b=-13}}$

$\bold{2.}\\\\\underbrace{(x+a)^2}_{(*)}+b=x^2+2ax+a^2+b\\\\x^2+4x-9=x^2+2ax+(a^2+b)\Rightarrow 4=2a\ \text{and}\ -9=a^2+b\\\\4=2a\qquad\text{divide both sides by 2}\\\\\dfrac{4}{2}=\dfrac{2a}{2}\\\\2=a\to \boxed{\bold{a=2}}\\\\\text{Substitute to the second equation:}\\\\-9=2^2+b\\\\-9=4+b\qquad\text{subtract 4 from both sides}\\\\-9-4=4-4+b\\\\-13=b\to \boxed{\bold{b=-13}}$

$\bold{3.}\\\\(x+a)^2+b-\text{it's a vertex form of an equation of a parabola}\\\\\text{Let}\ y=a(x-h)^2+k\ -\ \text{the euation of a parabola}\ y=ax^2+bx+c.\\\\\text{Then}\ h=\dfrac{-b}{2a},\ k=\dfrac{-(b^2-4ac)}{4a}\\\\x^2+4x-9\to a=1,\ b=4,\ c=-9\\\\h=\dfrac{-4}{2(1)}=\dfrac{-4}{2}=-2\\\\k=\dfrac{-(4^2-4(1)(-9))}{4(1)}=\dfrac{-(16+36)}{4}=\dfrac{-42}{4}=-13\\\\\text{Therefore}\\\\x^2+4x-9=(x+a)^2+b\\\\(x-(-2))^2+(-13)=(x+a)^2+b\\\\(x+2)^2-13=(x+a)^2+b\to\boxed{\bold{a=2,\ b=-13}}$

4 0

3 years ago