Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Solution:
Here we are given with the sides of the triangle as 5m, 16m and 5.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.
Hence no triangle can be made.
So the correct option is None.
Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?
Solution:
Here we are given with the sides of the triangle as 6m, 2m and 7m.
As the Triangle inequality we know that
The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.
Hence one triangle can be formed.
So the correct option is one.
Answer:
Step-by-step explanation:
2 + m
Rewrite with variable first.
m + 2
m + 2
Can’t be simplified further.
m - (-2)
Distribute negative sign.
m + 2
-2-m
Rewrite with variable first.
-m - 2
The last expression is not equivalent to m+2.
The chance of picking a almond cookie the first time:
you have 6 cookies, 3 of them are almond
So the chance of taking an almond cookie is
The second time there are 5 cookies left, 2 of them are almond cookies
The chance of taking an almond cookie is
To know the probability of picking two almond cookies in a row, multiply the changes:
The chance of taking two almond cookies is 1/5
P(B) = 2/15
The area of rectangle A is 5(7) = 35 in².
The area of rectangle B is 3(4) = 12 in²
The area of square C is 4(4) = 16 in²
The area of rectangle D is 3(9) = 27 in²
The total area of the figure is 35+12+16+27 = 90 in².
The probability of hitting B is 12/90 which simplifies to 2/15.