Answer:
You have the formula wrong.
The volume of a cylinder = PI * radius^2 * height
To find the height, the formula is:
height = volume / (PI*radius^2)
I'm assuming the radius = .6 meters so
height = 720 / (3.14159265 * .6^2)
height = 720 / 1.130973354
height = 636.61977 meters
Tp check your answer use this calculator: https://www.1728.org/diam.htm
Step-by-step explanation:
Answer:
a) y = -¼
Step-by-step explanation:
(-2x^6+5x+8)/(8x^6+6x+5)
Just divide the leading coefficients
-2/8 = -¼
Horizontal asymptote:
y = -¼
If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.
We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.
Therefore the box has length and breadth as 4 ft each and a height of 2 ft.
Answer:
108
Step-by-step explanation:
IT BE CORRACT
Answer:
x=2/3 or x=−1/2
Step-by-step explanation:
6x²−x=2
6x²−x−2=2−2
6x²−x−2=0
(3x−2)(2x+1)=0
3x−2=0 or 2x+1=0
x=2/3 or x=−1/2
