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3 years ago

Which of the following is the function representing the graph below?

Mathematics

1 answer:

iragen [17]3 years ago

7 0

You need to pick a point on the graph, then go through the list of choices
and see which one can produce the point you picked.

Look at the point on the graph right above the origin, where the graph
crosses the y-axis. At that point, x=0 and f(x) (or 'y') = 1 .

Now look at the choices, one at a time, and see whether (0, 1) fits.
I'll start at the bottom of the list:

--> f(x) = 4^(x-3)
When x=0, f(x) = 4^(-3) .
4^(-3) is not '1', so our point is not on this f(x).

--> f(x) = 4^x + 3
When x=0, f(x) = 4⁰ + 3 = 1 + 3 = 4
'4' is not '1', so our point is not on this f(x).

--> f(x) = 4^x - 3
When x=0, f(x) = 4⁰ - 3 = 1 - 3 = -2
'-2' is not '1', so our point is not on this f(x).

(Only one choice left.)

--> f(x) = 4^x
When x=0, 4^x = 4⁰ = 1
That's it ! Our point is on this f(x).
Which is lucky, because we were out of choices.

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Answer:

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2 years ago

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katrin [286]

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5 0

3 years ago

Billy starts counting backwards by 7, starting at 5907. when he reaches a single-digit number, he stops counting. what is the nu

Akimi4 [234]

If you do 5907/7 you will get 843.85714
Do 843*7=5901.
Then do 5907-5901=6
The final answer you will get is 6.

5 0

2 years ago

Solve for x in the following equation: 4(-5x-6) = 4(9x+4)

Romashka-Z-Leto [24]

Answer:

$- 20x - 6 = 36x + 4 \\ 36x + 20x = - 6 - 4 \\ 56x = - 10 \\ x = \frac{ - 10}{56} \\ x = - 0.17571428$

4 0

2 years ago

Find the real or imaginary solutions of each equation by factoring

anyanavicka [17]

Sum of 2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
for x²-4x+16=0
x= $\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}$
x= $\frac{4+/- \sqrt{16-64} }{2}$
x= $\frac{4+/- \sqrt{-48} }{2}$
x= $\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}$
x= $\frac{4+/- (i)(4\sqrt{3}) }{2}$
x= $2+/- 2i\sqrt{3}$

the roots are
x=-4 and 2+2i√3 and 2-2i√3

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3 years ago