All categories

4 years ago

Someone please help me with this

Mathematics

1 answer:

Bas_tet [7]4 years ago

4 0

Answer:

BE = 3 in; EF = 2 in; FC = 3 in

Step-by-step explanation:

∠EAD ≅ ∠AEB ≅ ∠EAB so ΔABE is isosceles and AB ≅ BE = 3 in.

Likewise, ∠FDC ≅ ∠FDA ≅ ∠DFC, so ΔDCF is isosceles and AB ≅ BC ≅ FC = 3 in.

Then EF = 8 in - 3in - 3 in = 2 in

You might be interested in

You are to place two minus signs and one plus sign between numbers one two three four five six seven eight nine to make a correc

lozanna [386]

Okay so 123-45-67+89=100
That should be the answer

4 0

3 years ago

arturo paid $8 in taxes on a purchase of $200. assuming the tac rate is the same, what would the tax be on a purchase of $150

Ludmilka [50]

Answer:

you would take 1/4 away from 8 because 1/4 of $200 is 50 so that makes the taxes 2$

Step-by-step explanation:

4 0

3 years ago

Find the perimeter of diameter 3.5 cm

sergiy2304 [10]

Answer: I am assuming it’s of a circle? So the answer would be rounded to 11.

Step-by-step explanation:

3 0

3 years ago

An athletic field is a 60 yd60 yd-by-120 yd120 yd rectangle, with a semicircle at each of the short sides. A running track 101

gregori [183]

Distance of each track are:

D₁ = 428.5 yd

D₂ = 436.35 yd

D₃ = 444.20 yd

D₄ = 452.05 yd

D₅ = 459.91 yd

D₆ = 467.76 yd

D₇ = 475.61 yd

D₈ = 483.47 yd

Explanation:

Given:

Track is divided into 8 lanes.

The length around each track is the two lengths of the rectangle plus the two lengths of the semi-circle with varying diameters.

Thus,

$D = 2(120) + 2. \frac{1}{2} \pi d\\\\D = 240 + \pi d$

Starting from the innermost edge with a diameter of 60yd.

Each lane is 10/8 = 1.25yd

So, the diameter increases by 2(1.25) = 2.5 yd each lane going outward.

So, the distances are:

D₁ = 240 + π (60) → 428.5yd

D₂ = 240 + π(60 + 2.5) → 436.35 yd

D₃ = 240 + π(60 + 5) → 444.20 yd

D₄ = 240 + π(60 + 7.5) → 452.05 yd

D₅ = 240 + π(60 + 10) → 459.91 yd

D₆ = 24 + π(60 + 12.5) → 467.76 yd

D₇ = 240 + π(60 + 15) → 475.61 yd

D₈ = 240 + π(60 + 17.5) → 483.47 yd

4 0

4 years ago

The table shows a proportional relationship between the number of pounds of bananas purchased and the total cost of bananas.

Liula [17]

Answer:

Choice A, C and E

Step-by-step explanation:

Your table is poorly presented

Given

x y

$\begin{array}{cc} {3} & {1.47} \ \\ {5} & {2.45} \ \\ {9} & {4.41} \ \ \end{array}$

First, we calculate the constant of proportionality (k)

$k = \frac{y}{x}$

For (3,1.47)

$k = \frac{1.47}{3}$

$k = 0.49$

For (5,2.45)

$k = \frac{2.45}{5}$

$k = 0.49$

For (9,4.41)

$k = \frac{4.41}{9}$

$k = 0.49$

From the above calculations, the constant of proportionality is 0.49.

So, the usable rows must also have 0.49 as their constant of proportionality

Choice A

$(x,y) = (2,0.98)$

$k = \frac{0.98}{2}$

$k = 0.49$ --- This is usable

Choice B

$(x,y) = (7,4.45)$

$k = \frac{4.45}{7}$

$k = 0.64$ --- This is not usable

Choice C

$(x,y) = (6,2.94)$

$k = \frac{2.94}{6}$

$k = 0.49$ --- This is usable

Choice D

$(x,y) = (1,0.54)$

$k = \frac{0.54}{1}$

$k = 0.54$ ---- This is not usable

Choice E

$(x,y) = (8,3.92)$

$k = \frac{3.92}{8}$

$k = 0.49$ --- This is usable

5 0

3 years ago