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Helen [10]
4 years ago
14

NEED HELP FAST!!!!!!!!!!!

Mathematics
1 answer:
erica [24]4 years ago
7 0

Answer:a=3/4

b=3/4

Step-by-step explanation:

3a+5b=6

9a+7b=12

-3(3a+5b)=-3(6)

9a+7b=12

-9a-15b=-18

9a+7b=12

-8b=-6

b=3/4

3a+5(3/4)=6

3a+15/4=6

3a=9/4

a=3/4

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A rectangle has a length of 2x + 7 and a width of 3x + 8y. Write and simplify an expression for the perimeter of that rectangle.
IrinaVladis [17]
This is your information...
Length: 2x + 7 
Width: 3x + 8y 
Perimeter: 2(l + w) ...or... 2l + 2w
Now let's substitute...
2(l + w)
l = 2x + 7
w = 3x + 8y
2(2x+7+3x+8y)
Now combine the like terms: 
2(5x+7+8y)
Now distribute the number 2:
10x+14+16y
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I HOPE THIS HELPED!!!! :D ;D
4 0
3 years ago
What is the square root of 16x36
Alinara [238K]
Sqrt of 16 is 4.
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6 0
3 years ago
Find the answer in vertex form.y=x^2-6x+7
RoseWind [281]
3,-2 would be the answer find the roots first <span><span>   </span><span><span><span><span> y(x)=x^2-6x+7</span></span></span></span>s<span><span> <span>
Find roots


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3 0
4 years ago
at a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. Th
VladimirAG [237]

Answer:

The number of tickets sold to the public was 375

Step-by-step explanation:

<u><em>The complete question is</em></u>

At a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. The students paid $15 and public $25. When all the tickets were sold, $10,500 was collected. How many tickets were sold to the public?

Let

x ----> number of tickets sold to the students

y ----> number of tickets sold to the public

we know that

x+y=450 ----> equation A

15x+25y=10,500 ----> equation B

Solve the system by graphing

The solution is the intersection point both graphs

using a graphing tool

The solution is the point (75,375)

see the attached figure

therefore

The number of tickets sold to the public was 375

6 0
4 years ago
PLS HELP WILL GIVE BRAINLEST 100Pts!!!
LenaWriter [7]

Answer:

<h3>Car A</h3>
  • Initial price = $30000
  • Initial depreciation = 20%
  • Further yearly depreciation = $2000

<u>The equation to reflect the above:</u>

  • A(t) = 30000 - 0.2*30000 - 2000t ⇒
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<h3>Car B</h3>
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  • Initial depreciation = 10%
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<u>The equation to reflect the above:</u>

  • B(t) = 25000 - 0.1*25000 - 1500t ⇒
  • B(t) = 22500 - 1500t
5 0
3 years ago
Read 2 more answers
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