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IgorLugansk [536]

2 years ago

14

There are two slices of pizza left. The original pizza had four slices of equal size. What kind of angles are the two slices tog

ether? Select all that apply.

2 answers:

Troyanec [42]2 years ago

6 0

Answer:

I think it’s C

Step-by-step explanation:

zubka84 [21]2 years ago

3 0

The answer would be B, Supplementary Angle, Since half the circle would be 180 degrees also if this isn’t enough information,

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Kamila [148]

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3 years ago

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garri49 [273]

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2 years ago

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LekaFEV [45]

I'm pretty sure both B and C equal 12 as well
Since the triangle equals 180 and the angels are all congruent

7 0

2 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

1 year ago

7. Marco is making beaded bracelets. Each

stiks02 [169]

One way to find the least common multiple of two numbers is to first list the prime factors of each number.

8 = 2 x 2 x 2

Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

2: three occurrences

3: one occurrence

So, our LCM should be

2 x 2 x 2 x 3 = 24.

So, Marco can buy, at the very least, 24 beads of each color to have equal colors of beads.

4 0

2 years ago