Ask question

Ask question

All categories

3 years ago

10

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

orts. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow. 6 4 6 8 7 7 6 3 3 8 10 4 8 7 8 7 5 9 5 8 4 3 8 5 5 4 4 4 8 4 5 6 2 5 9 9 8 4 8 9 9 5 9 7 8 3 10 8 9 6 Develop a 95% confidence interval estimate of the population mean rating for Miami. (Round your answers to two decimal places.)

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Answer:

M = 6.34, 95% CI [5.7468, 6.9332].

You can be 95% confident that the population mean (μ) falls between 5.7468 and 6.9332.

Step-by-step explanation:

Calculation

M = 6.34

Z = 1.96

sM = √(2.142/50) = 0.3

μ = M ± Z(sM)

μ = 6.34 ± 1.96*0.3

μ = 6.34 ± 0.5932

Check the attached file for more explanation

You might be interested in

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

Can anyone help with these maths questions about transformations please?

salantis [7]

A. Reflection over y = 2

B. Reflection over y axis, reflection over y = 1

C. I'm guessing you just have to draw this one, just put the center on (2,0) and enlarge it by the scale factor

8 0

3 years ago

its 76 degrees fahrenheit at the 6000-foot level of a mountain, and 49 degrees Fahrenheit at the 12000-foot level of the mountai

brilliants [131]

$T = \frac{-9}{2}x + 103$ is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.

<em><u>Solution:</u></em>

The linear equation in slope intercept form is given as:

T = cx + k ------ (i)

Where "t" is the temperature at an elevation x

And x is in thousands of feet

<em><u>Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain</u></em>

Given, when c = 6 thousand ft and $T = 76^{\circ}$ fahrenheit

This implies,

From (i)

76 = c(6) + k

76 = 6c + k

⇒ k = 76 - 6c ----- (ii)

<em><u>Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain</u></em>

Given, when c = 12 thousand ft and $T = 49^{\circ}$ fahrenheit

This implies,

From (i)

49 = c(12) + k

49 = 12c + k

Substitute (ii) in above equation

49 = 12c + (76 - 6c)

49 = 12c + 76 - 6c

49 - 76 = 6c

6c = -27

$c = \frac{-9}{2}$

Substituting the value of c in (ii) we get

$k = 76 - 6( \frac{-9}{2})\\\\k = 76 + 27 = 103$

Substituting the value of c and k in (i)

$T = \frac{-9}{2}x + 103$

Where "x" is in thousands of feet

Thus the required linear equation is found

5 0

3 years ago

Solve for x <br> 5x + 2 = 17

Ymorist [56]

Answer:

r

Step-by-step explanation:

r

8 0

3 years ago

Read 2 more answers

In the figure below, L N equals 4 x minus 7 and M O equals 2 x plus 13. For which value of x is the figure a rectangle?

Georgia [21]

For this case we have the following data:

$LN = 4x-7$

$MO = 2x + 13$

So that the figure can be a rectangle, its diagonals must be equal, that is, $LN = MO$

In this way we have:

$4x-7 = 2x + 13$

Clearing x we have:

$4x-2x = 13 + 7 \\2x = 20$

$x=\frac{20}{2} \\x = 10$

Thus, x must be equal to 10 so that the figure is a rectangle.

Answer:

$x = 10$

Option A

3 0

3 years ago