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3 years ago

14

If angles A, B, C and D of the quadrilateral ABCD, taken in order, are in the ratio 3:7:6:4, then name the type of quadrilateral

ABCD

2 answers:

lesya692 [45]3 years ago

8 0

Answer:whats the full questions?

Step-by-step explanation:

aniked [119]3 years ago

3 0

Answer:

the quadrilateral would be trapezium

Step-by-step explanation:

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Solve the equation 5(w - 12) - 24 = 3(w + 2)

notsponge [240]

Answer:

45

Step-by-step explanation:

5w - 60 - 24 = 3w + 6

5w - 3w = 6 + 60 + 24

2w = 90

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3 years ago

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2 years ago

The area of triangle ABC is 3√2 square inches. Find the measure of the acute angle, A, if b = 9 meters and c = 2 meters.

taurus [48]

Answer:

$A\approx 28^{\circ}$

Step-by-step explanation:

Please find the attachment.

We have been given that area of triangle ABC is 3√2 square inches.

$\text{Area}=\frac{1}{2}\text{Base}\times \text{height}$

We know that area of triangle an be found using trigonometry as:

$\text{Area}=\frac{1}{2}\times c\times h$

$\text{sin}(A)=\frac{h}{9}\\h=9\cdot \text{sin}(A)$

$3\sqrt{2}=\frac{1}{2}\times 2\times 9\cdot \text{sin}(A)$

$3\sqrt{2}=9\cdot \text{sin}(A)$

$9\cdot \text{sin}(A)=3\sqrt{2}$

$\text{sin}(A)=\frac{3\sqrt{2}}{9}$

$\text{sin}(A)=\frac{\sqrt{2}}{3}$

Now, we will use inverse sine to find the value of angle A as:

$A=\text{sin}^{-1}(\frac{\sqrt{2}}{3})$

$A=28.1255057^{\circ}$

$A\approx 28^{\circ}$

Therefore, the measure of angle A is approximately 28 degrees.

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3 years ago

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bonufazy [111]

Answer:

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