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galben [10]
4 years ago
14

Use Gauss-Jordan elimination to solve the following linear system.

Mathematics
1 answer:
Nataliya [291]4 years ago
5 0
C I have done this before
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you deposited $5500 in a account that pays 3.6% annual interest. find the balance after 2 years if the interest is compound mont
Sedaia [141]

Answer:

$5,909.97

Step-by-step explanation:

We will use the compound interest formula for this problem as shown below:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, change 3.6% into a decimal:

3.6% -> \frac{3.6}{100} -> 0.036

Now plug in the values:

A=5,500(1+\frac{0.036}{12})^{12(2)}

A=5,909.97

After 2 years, the balance would be $5,909.97

6 0
3 years ago
Ed planned to read 25 pages a day of his favorite book by some deadline. However, he read 8 pages more a day and there were just
GaryK [48]

Answer:

175 pages

Step-by-step explanation:

Let's call 'd' the number of days before the deadline, and 'n' the total number of pages of the book.

We have the following equations:

(1) 25 d = n --> if we multiply the number of pages per day (25) times the number of days (d), we get the total number of pages of the book (n)

(2) (25+8)(d-2)=n-10 --> he reads 8 pages more per day (so, 25+8), for a number of days equal to (d-2) (d is the deadline), and he reads a total of n-10 pages (because only 10 are left)

We can substitute (1) into (2) and we find:

33(d-2)=25d-10\\33d-66=25d-10\\33d-25d=66-10\\8d=56\\d=7

So, the deadline is 7 days, and from eq.(1) we find the number of pages in the book:

n=25d=25 (7)=175


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3 years ago
HEY GUYS I NEED HELP PLZZ! 20 POINTS?? Plz explain how yall found yo answer plzz!
Korvikt [17]
Bacon is good for you. you should try it
7 0
3 years ago
Find the probability of no failures in five trails of a binomial experiment in which the probability of success is 30%
anastassius [24]
The probability of no failures in five trials is 0.2%.
8 0
3 years ago
Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x " #50 cm and x " )50 cm. Th
Scorpion4ik [409]

Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x = -50 cm and x = +50 cm. The charge densities on the planes are -50 nC/m² and +25 nC/m², respectively. What is the magnitude of the potential difference between the origin and the point on the x axis at x = +80 cm? (Hint:Use Gauss’ law.)

Answer:

ΔV = 2520 V

Step-by-step explanation:

We are given;

Charge density 1; σ1 = -50 nC/m² = -50 × 10^(-9) nC/m²

Charge density 2; σ2 = +25 nC/m² = +25 × 10^(-9) nC/m²

Now, formula for electric field strength is;

E = -(½ε)(|σ1| ± |σ2|)

ε is vacuum permittivity with a constant value as 8.85 × 10^(−12) C²/N.m²

|σ1| and |σ2| means we are taking the absolute values and would therefore not use the negative sign attached to them.

Now, in between x = 0 cm(0 m) and 50 cm (0.5 m), electric field generated by both charge densities would be in the same direction and thus;

E_in = -(½ε)(|σ1| + |σ2|)

E_in = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) + (25 × 10^(-9))]

E_in = -4200 V/m

In contrast, when x ≥ 50 cm (0.5 m), electric field generated by both charge densities would be in opposite directions and thus;

E_out = -(½ε)(|σ1| - |σ2|)

E_out = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) - (25 × 10^(-9))]

E_out = 1400 V/m

The magnitude of the potential difference from the origin to x = 80 cm(0.8 m) is calculated as attached;

From the attachment, we see that;

ΔV = 2520 V

6 0
4 years ago
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