Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer: if its a proper fraction, 1 is always greater. Just know that because something doesnt look right here!
Step-by-step explanation:
Answer- A
1 and 4, 6 and 7
Explanation- vertical angles are each of the pairs of opposite angles made by two intersecting lines.
Y-intercept is a value of function, when x=0.
f(0) = 0
g(x) = <span>4 sin(4x) − 3
g(0) = 4sin(4*0) - 3 = -3
0>-3,
so </span><span>a) f(x) has greater y-intercept.</span>
The answer would be set A because Set B start low on both, Set C Starts low on one and high on another but also has decimals, set D starts both low. So your answer would be A.
I also know because I took the test and that is the answer I did ans it said it was correct.