Select TWO expressions that contain a coefficient of 4.

If 2 is added to both the numerator and denominator of a fraction its value becomes half. If two is subtracted from both the num

Hitman42 [59]

Answer:

The original fraction is $\frac{6}{14}$ .

Step-by-step explanation:

Solution,

Let the fraction be' $\frac{x}{y}$ '.

Where 'x' is the numerator and 'y' is the denominator.

Now according to question, if 2 is added to both the numerator and denominator the value of the fraction becomes 1/2.

So, framing the above sentence in equation form, we get;

$\frac{x+2}{y+2}=\frac{1}{2}$

On using cross multiplication method, we get;

$2(x+2)=y+2\\\\2x+4=y+2\\\\2x+4-2=y\\\\\therefore\ y=2x+2\ \ \ \ equation\ 1$

Now according to question, if 2 is Subtracted to both the numerator and denominator the value of the fraction becomes 1/3.

So, framing the above sentence in equation form, we get;

$\frac{x-2}{y-2}=\frac{1}{3}$

On using cross multiplication method, we get;

$3(x-2)=y-2\\\\3x-6=y-2\\\\3x-y=-2+6\\\\3x-y=4 \ \ \ \ equation\ 2$

Now Substituting the equation 1 in equation 1 we get;

$3x-y=4\\\\3x-(2x+2)=4\\\\3x-2x-2=4\\\\3x-2x=4+2\\\\x=6$

Now Substituting the value of x in equation 1 we get;

$y=2x+2\\\\y=2\times6+2 = 14$

Hence The original fraction is $\frac{6}{14}$ .

4 0

3 years ago

Vicky did a survey to answer the following question: What is the average fitness score of grade 8 students? The mean fitness sco

mario62 [17]

The mean is calculated by adding up all of the data points and then dividing the sum by the amount of points added.

The mean fitness score was 3.2 points. If all of the students scored the same thing (3.2 points) then this would be the fitness score of each student.

Thus, the answer is D. 3.2 points.

3 0

2 years ago

The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a

Evgesh-ka [11]

The complete question is as follows.

The equation a = $\frac{1}{2}(b_1 + b_2 )h$ can be used to determine the area , a, of a trapezoid with height , h, and base lengths, $b_1$ and $b_2$ . Which are equivalent equations?

(a) $\frac{2a}{h} - b_2 = b_1$

(b) $\frac{a}{2h} - b_2 = b_1$

(c) $\frac{2a - b_2}{h}$ = $b_1$

(d) $\frac{2a}{b_1 + b_2} = h$

(e) $\frac{a}{2(b_1 + b_2)}$ = h

Answer: (a) $\frac{2a}{h} - b_2 = b_1$ ; (d) $\frac{2a}{b_1 + b_2} = h$ ;

Step-by-step explanation: To determine $b_1$ :

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = ( $b_1 + b_2$ )h

$\frac{2a}{h} = b_1 + b_2$

$\frac{2a}{h} - b_2 = b_1$

To determine h:

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{(b_1 + b_2)}$ = h

To determine $b_2$

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{h} = (b_1 + b_2)$

$\frac{2a}{h} - b_1 = b_2$

Checking the alternatives, you have that $\frac{2a}{h} - b_2 = b_1$ and $\frac{2a}{(b_1 + b_2)}$ = h, so alternatives A and D are correct.

4 0

3 years ago

Helpppppoppp meeeeeee

madreJ [45]

Answer:

9 feet

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Erin has scanned a 4 × 5-inch postcard, and she wants to reduce it to make a graphic for her Web site. She will use a scale fact

Rasek [7]

Just multiply both dimensions by 2 to make it into centimeters.

Therefore,

4*2 x 5*2 (in inches) will be:

8cm x 10cm (in centimeters)

We conclude that the dimensions of her postcard into a graphic on her web page will be 8x10 in centimeter units.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

6 0

3 years ago