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RUDIKE [14]
3 years ago
6

Matthew is training to participate in a half marathon. The table below shows the number of miles he runs in weeks 1 and 2. Week

Number of Miles Run 1 12.5 2 13.5 Each week, Matthew increases the number of miles he runs in the previous week by the same percent. How many miles does Matthew run in week 3? Do not round your answer. a0 miles
Mathematics
2 answers:
frosja888 [35]3 years ago
7 0

Answer: There is 14.5 miles run by Matthew in week 3.

Step-by-step explanation:

Since we have given that

Week   Number of miles

1                         12.5

2                        13.5

First we will find the slope :

(1,12.5) and (2,13.5)

So, Slope would be

\dfrac{y_2-y_1}{x_2-x_1}\\\\=\dfrac{13.5-12.5}{2-1}\\\\=1

So, equation of line would be

y-y_1=m(x-x_1)\\\\y-12.5=1(x-1)\\\\y-12.5=x-1\\\\y-x=12.5-1\\\\y-x=11.5

We need to find the number of miles in week 3.

So, we put x = 3,

y-3=11.5\\\\y=11.5+3\\\\y=14.5

Hence, there is 14.5 miles run by Matthew in week 3.

Maurinko [17]3 years ago
4 0

Matthew ran 14.58 miles in week 3

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vagabundo [1.1K]
s-18=70\implies s-18+18=70+18\implies s+(18-18)=88\implies s=88
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3 years ago
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Susan Marciano invested part of her 19000 bonus in a fund that paid an 11% profit and invested the rest in stock that suffered a
ioda

The amount invested at 11% is ​$5,000

The amount invested in stock is ​$14,000

What is the net profit on both investments?

The profit of each investment is the rate of return or loss multiplied by the amount invested

Let us assume that x was invested at 11% and the remaining 19000-x was invested at a loss rate of 3%

net profit=(11%*x)+(19000-x)*-3%

net profit=130

130=(11%*x)+(19000-x)*-3%

130=0.11x-570+0.03x

130=0.14x-570

130+570=0.14x

700=0.14x

x=700/0.14

x=$5,000

Amount invested in stock=19000-x

Amount invested in stocks=19000-5000

Amount invested in stocks=$14,000

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1 year ago
Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے
Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

A=\frac{8}{3} \sqrt{p h} \cdot h

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\

Generally, the equation for the Area is mathematically given as

& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\

&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h

A=\frac{8}{3} \sqrt{p h} \cdot h

In conclusion,  the equation for the Area is

   

A=\frac{8}{3} \sqrt{p h} \cdot h

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2 years ago
Given the parent function f(x)=x^2 in red, write the equation for the transformed function g(x) in green.
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Answer:

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Step-by-step explanation:

The parabola got thinner, so to show that, you put a 2 <u><em>before</em></u> x²<em> </em>to show that the graph was <em>dilated </em>(or thinned) by a factor of <em>2 </em>(Note: this number can also be <em>negative</em>, so if the dilation factor is negative, it's okay). Since the parabola shifts up by <em>1</em>, you then add + 1<em> </em><em><u>after</u></em> x² to show the positive upward shift.

Your full equation would look like this: g(x) = 2x² + 1

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Misha Larkins [42]

Answer:

9/10

30%

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So 3/10 which is 0.3 which is the same as 30%.

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