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Zigmanuir [339]
3 years ago
6

Formaldehyde has the formula ch2o. how many molecules are there in 0.11 g of formaldehyde

Chemistry
1 answer:
jeka57 [31]3 years ago
6 0
Answer: 2.21 x 10^{21} molecule

To answer this question, you need to know the formaldehyde molecular mass.
Formaldehyde molecular weight would be 12+ 1(2) + 16= 30 g/mol
After knowing the molecular mass you can count how many molecules by multiplying it by Avogadro's number. The calculation would be:
0.11g / (30g/mol) x 6.022140857 × 10^{23} = 0.02208 x 10^{23} = 2.21 x 10^{21} 
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5. How many formula units are in 1.62 moles of magnesium iodide?
PIT_PIT [208]

Answer: 9.75 x10^23

Explanation: you do 6.02x10^23 times 1.62. And then round to three digits.

6 0
3 years ago
Which shows the correct relationship between the molecular formula and the empirical formula for C2H10N2?
SIZIF [17.4K]
The correct answer is A. molecular formula = 2 x empirical formula

The given compound C2H10N2 is the molecular formula because the ratios of the elements are not reduced into lowest terms (empirical formula). To get the empirical formula, the ratios must be reduced to the smallest possible integral ratio which gives CH5N. As a result, the ratio between both formulas is 2.
3 0
3 years ago
Read 2 more answers
about how many times as much volume does a gas occupy compared to the same substance as a liquid or solid under normal condition
7nadin3 [17]

Answer:

Gases don't have definite volume. Gas molecules occupy all available space.

Explanation:

Consider the example of water. Which is present in three state solid, liquid and gas. In the form of ice its volume is less as compared to the liquid and gas, because molecules are tightly packed. If we melt the same ice we observe the volume is increase because molecules are now apart from each other. The distance between the molecules of water increased. If the same amount of water is evaporated the molecule of water will occupy all available space , and the distance between the water molecules get increased and inter molecular forces becomes negligible.

Properties of gases:

Molecule of gases randomly move every where and occupy all available space.

Gases don't have definite volume and shape.

Their densities are very low as compared to the liquid and solids.

Gas molecules are at long distance from each other therefore by applying pressure gases can be compressed.

The very weak inter molecular forces are present between gas molecules.

Properties of Liquid:

Liquid have definite volume but don,t have definite shape.

Their densities are high as compared to the gases but low as compared to the solids.

In liquid, molecules are close to each other and have greater inter molecular forces as compared to the gas molecules.

Properties of solids:

Solids have definite volume and shape.

In solids molecules are tightly pack and very close to each other.

Their melting and boiling point are every high.

The densities of solids are also very high as compared to the liquid and gas.

There are very strong inter molecular forces are present between solid molecules.

6 0
3 years ago
Total solar eclipses are common and happen every month at the beginning of the new lunar cycle.
Bogdan [553]
False, solar eclipses happen when the moon moves between the Sun and the Earth, blocking the Sun's rays and casting a shadow on Earth. It happens about once every 18 months (on average)
7 0
4 years ago
50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximat
trapecia [35]

Answer:

4.76

Explanation:

In this case, we have to start with the <u>buffer system</u>:

CH_3COOH~->~CH_3COO^-~+~H^+

We have an acid (CH_3COOH) and a base (CH_3COO^-). Therefore we can write the <u>henderson-hasselbach reaction</u>:

pH~=~pKa+Log\frac{[CH_3COO^-]}{[CH_3COOH]}

If we want to calculate the pH, we have to <u>calculate the pKa</u>:

pH=-Log~Ka=4.76

According to the problem, we have the <u>same concentration</u> for the acid and the base 0.1M. Therefore:

[CH_3COO^-]=[CH_3COOH]

If we divide:

\frac{[CH_3COO^-]}{[CH_3COOH]}~=~1

If we do the Log of 1:

Log~1=~zero

So:

pH~=~pKa

With this in mind, the pH is 4.76.

I hope it helps!

8 0
3 years ago
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