A solution with a ph of 2.0 has a hydrogen ion concentration ten times greater than a solution with a ph

2NaN3 -> 3N2+Na How many moles are there of NaN3

Igoryamba

2.
The mole ratio is based on the coefficients for each component, so in this case it would be 2:3:1. So, if that is the ratio of the number of moles for each component, then there are 2 miles for NaN3

7 0

3 years ago

Read the false statement. There are 18 periods in the periodic table. Which answer choice rewords the false statement so it is t

Artyom0805 [142]

Answer:

C

Explanation:

On the periodic table, there are 8 periods. The periods are the horizontal bands on the periodic table. There are two distinct bands on the modern periodic table. These are the horizontal and the vertical bands. While the vertical bands are for the groups, the horizontal bands are for the periods.

There are 8 distinct horizontal bands on the periodic table. Although there are usually two bands which are placed beneath the last band on the periodic table. It must be noted that these bands are part of the main group elements. It is only a similarity in property on their path that make them positioned there.

For two elements to be in the same period in the periodic table however, it is expected that they have the same number of electron shells.

For example, hydrogen and helium are placed in period one because they only have the K shell of electrons

4 0

4 years ago

Read 2 more answers

The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351

ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of $N_2$ and $H_2$ by using ideal gas equation.

For $N_2$ :

$PV_{N_2}=n_{N_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $N_2$ gas = 1580 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{N_2}=70.49mole$

For $H_2$ :

$PV_{H_2}=n_{H_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $H_2$ gas = 3510 L

n = number of moles $H_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{H_2}=156.6mole$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 3 mole of $H_2$ react with 1 mole of $N_2$

So, 156.6 moles of $H_2$ react with $\frac{156.6}{3}\times 1=52.2$ moles of $N_2$

From this we conclude that, $N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of $N_2$ reactant (unreacted gas).

Excess moles of $N_2$ reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

$PV=nRT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K$

$V=409.9L$

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0

3 years ago

CaCO3 (s) + 176 KJ à CaO (s) + CO (g)

statuscvo [17]

Answer:

its d

Explanation:

3 0

3 years ago

PLZ HELP WILL MARK BRAINLIEST

snow_lady [41]

Answer:

The male cone

Explanation:

The male cones, which produce pollen, are usually herbaceous and much less conspicuous even at full maturity.

3 0

4 years ago