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tatiyna
3 years ago
10

Balance the equations below by adding coefficients. Enter a number in each blank, entering "1" when necessary.

Chemistry
2 answers:
12345 [234]3 years ago
7 0

Answer:

1CO2 → 1C+ 1O2

1Fe2 + 1O2 → 2FeO

2Al + 3CuO → 1Al2O3 + 3Cu

Explanation:

1. CO2 → C+O2

On both sides we have 1x C and 2X O.

The equation is balanced

1CO2 → 1C+ 1O2

2. Fe2 + O2 → FeO

On the left side we 2x Fe, On the right side we have 1x Fe (in FeO). To balance the amount of Fe on both sides, we have to multiply FeO (on the right) by 2. If we multiply FeO by 2, we'll have 2x O on the right side. This is the same amount on the left side. The equation is balanced

1Fe2 + 1O2 → 2FeO

3. Al + CuO → Al2O3 + Cu

On the left side we have 1x Al, on the right side we have 2x Al. To balance the amount of Al we have to multiply Al (on the left) by 2.

We have 3x O on the right side, on the left side we have 1x O. To balance the amount of O on both sides, we have to multiply CuO (on the left) by 3.

We have 3x Cu on the left side (in 3CuO) and 1x Cu on the right side. To balance the amount of Cu we have to multiply Cu (on the right ) by 3.

Now the equation is balanced.

2Al + 3CuO → 1Al2O3 + 3Cu

neonofarm [45]3 years ago
3 0

Answer:

1. CO₂ → C + O₂

2. Fe₂ + O₂ → 2FeO

3. 2Al + 3CuO→  Al₂O₃  +  3Cu

Explanation:

1. 1 mol of CO₂ decomposes to 1 mol of C and 1 mol of oxygem

2. 1 mol of Fe₂ reacts with 1 mol of oxygen to produce 2 moles of iron (II) oxide

3. 2 moles of Al, reacts with 3 moles of cupper(II) oxide to produce 1 mol of aluminum dioxide and 3 moles of cupper

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xz_007 [3.2K]

The number of oxygen atoms = 3

Mass = 24 g

<h3>Further explanation</h3>

The formula of a compound shows the composition of the constituent elements

CaCO₃ is composed of 3 types of elements, namely Ca, C and O

The amounts of each of these elements in the compound CaCO₃:

  • Ca = 1
  • C = 1
  • O = 3

So the number of oxygen atoms = 3

mass of Oxygen :

\tt mass~O=\dfrac{3\times Ar~O}{MW~CaCO_3}\times mass~CaCO_3\\\\mass~O=\dfrac{3\times 16}{100}\times 50=24~g

5 0
2 years ago
What is the structural formula of 2-methylbutan-2-ol (sometimes called 2-methyl-2-butanol)?
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<span>The structural formula of 2-methylbutan-2-ol is in Word document below.
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4 0
3 years ago
Read 2 more answers
Choose the answer that best completes the following statement: When an aluminum atom reacts so as to attain a noble gas electron
boyakko [2]

The options

Select one:

a. a 3- ion forms.

b. the noble gas configuration of argon is achieved.

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d. the atom gains five electrons.

Answer:

c. the result is a configuration of 1s2 2s2 2p6.

Explanation:

Aluminium atom has atomic number of 13 , hence the number of electron is 13 for a neutral atom of aluminium. When aluminium atom reacts with other elements it usually gives out three electron to attain the octet configuration.

The cation representation of aluminium is Al3+ because it has loss three electron to attain the octet rule. Aluminium will be left with 10 electrons after losing 3 of it electrons. The electronic configuration will be represented as follows after losing three electrons;

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At this stage the octet rule has been achieved as it will be represented as

2  8.  The first energy shell now contains two electron and the second energy shell contains 8 electrons.

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3 years ago
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alexdok [17]

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

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P_2 = final pressure of gas = 1.0 atm

V_1 = initial volume of gas = 250 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 15^oC=273+15=288K

T_2 = final temperature of gas = 27^oC=273+27=300K

Now put all the given values in the above equation, we get:

\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}

V_2=625mL

Therefore, the volume of the bubble is, 625 mL

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