All categories

3 years ago

Balance the equations below by adding coefficients. Enter a number in each blank, entering "1" when necessary.

Chemistry

2 answers:

12345 [234]3 years ago

7 0

Answer:

1CO2 → 1C+ 1O2

1Fe2 + 1O2 → 2FeO

2Al + 3CuO → 1Al2O3 + 3Cu

Explanation:

1. CO2 → C+O2

On both sides we have 1x C and 2X O.

The equation is balanced

1CO2 → 1C+ 1O2

2. Fe2 + O2 → FeO

On the left side we 2x Fe, On the right side we have 1x Fe (in FeO). To balance the amount of Fe on both sides, we have to multiply FeO (on the right) by 2. If we multiply FeO by 2, we'll have 2x O on the right side. This is the same amount on the left side. The equation is balanced

1Fe2 + 1O2 → 2FeO

3. Al + CuO → Al2O3 + Cu

On the left side we have 1x Al, on the right side we have 2x Al. To balance the amount of Al we have to multiply Al (on the left) by 2.

We have 3x O on the right side, on the left side we have 1x O. To balance the amount of O on both sides, we have to multiply CuO (on the left) by 3.

We have 3x Cu on the left side (in 3CuO) and 1x Cu on the right side. To balance the amount of Cu we have to multiply Cu (on the right ) by 3.

Now the equation is balanced.

2Al + 3CuO → 1Al2O3 + 3Cu

neonofarm [45]3 years ago

3 0

Answer:

1. CO₂ → C + O₂

2. Fe₂ + O₂ → 2FeO

3. 2Al + 3CuO→ Al₂O₃ + 3Cu

Explanation:

1. 1 mol of CO₂ decomposes to 1 mol of C and 1 mol of oxygem

2. 1 mol of Fe₂ reacts with 1 mol of oxygen to produce 2 moles of iron (II) oxide

3. 2 moles of Al, reacts with 3 moles of cupper(II) oxide to produce 1 mol of aluminum dioxide and 3 moles of cupper

You might be interested in

Which fact below is describing a base?

QveST [7]

7 to 49 10 to 100. 30 Secs. 3. What is the pH value of pure water? 0 3 7 10 ... How do acids taste? bitter sour sweet salty. 30 Secs. 7. How do bases taste? bitter ... 8. Which kind of solution would react with a metal? acidic basic neutral water ... cocoa has a bitter taste. It is most likely which of the following? acid base neutral

6 0

3 years ago

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0

3 years ago

A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t

FrozenT [24]

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

4 0

3 years ago

Notice in the picture of sedimentary rocks, there is one layer on top of the other. The oldest rocks are on the bottom of the pi

amm1812

Answer:

A. Superposition

Explanation:

A law of geochronology, stating that in any undisturbed sequence of rocks deposited in layers, the youngest layer is on top and the oldest on bottom, each layer being younger than the one beneath it and older than the one above it.

3 0

3 years ago

A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your

amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{Volume in liter}}$