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3 years ago

Which type of star has the lowest density?

Chemistry

2 answers:

julsineya [31]3 years ago

8 0

The white dwarf has the lowest density of the stars listed. Hope this helps and have a nice day!

Otrada [13]3 years ago

3 0

Answer:

A. giant

Explanation:

Giant stars are older and hotter than dwarf stars. They can be thousands of times brighter than our Sun. They have low density (although they are large) as opposed to the white dwarf which is one of the celestial bodies with the highest density.

Among the giant stars we can mention the red giants and the blue giants.

The end of the lives of these stars is marked by explosive cosmic events, such as supernovae, which can give rise to black holes.

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100 points! Formation of an Ion

djyliett [7]

$\huge\underline\pink {Answer}$

If every oxygen ion is combined with an aluminium ion has a charge of -2,the charge of each aluminum ion would be -3.

Uncharged Aluminum atom must need to lose it's electrons,in order to form the bond with oxygen which has vacant orbitals

ion

atom that has a positive or negative charge because it lost or gained one or more electrons

chemical bond

the attractive force that holds atoms or ions together

ionic bond

a chemical bond in which one atom loses an electron and the other atom gains electrons to form ions

chemical formula

a combination of chemical symbols and numbers to represent a substance

covalent bond

bond formed by the sharing of electrons between atoms

8 0

3 years ago

Read 2 more answers

A student wishes to calculate the experimental value of Ksp for AgI. S/he follows the procedure in Part 3 and finds Ecell to be

Ymorist [56]

Answer:

a) [Ag+]dilute = 6.363 × 10⁻¹⁶ M

b) 1.273 × 10⁻¹⁶

c) 2.629×10⁻¹⁹ M Thus; the value for [Ag+ ]dilute will be too low

Explanation:

In an Ag | Ag+ concentration cell ,

The anode reaction can be written as :

Ag ----> Ag+(dilute) + e- &:

The cathode reaction can be written as:

Ag+(concentrated) + e- ----> Ag

The Overall Reaction : is

Ag+(concentrated) -----> Ag+(dilute)

However, the Standard Reduction potential of cell = E°cell = 0

( since both cathode and anode have same Ag+║Ag )

Also , given that the theoretical slope is - 0.0591 V

Therefore; the reduction potential of cell ; i.e

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

0.839 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 14.1963

[Ag+]dilute = $\mathbf{10^{-14.1963} }$ × 1.0 × 10⁻¹ M

[Ag+]dilute = 6.363 × 10⁻¹⁶ M

AgI ----> Ag + (dilute) + I⁻

So , Solubility product = Ksp = [Ag⁺]dilute × [I⁻]

= 6.363 × 10⁻¹⁶ M × 0.20 M

= 1.273 × 10⁻¹⁶

c) If s/he mistakenly uses 1.039 V as Ecell; then the value for [Ag+]dilute will be :

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

1.039 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 17.5804

[Ag+]dilute = $\mathbf{10^{-17.5804} }$ × 1.0 × 10⁻¹ M

[Ag+]dilute = 2.629×10⁻¹⁹ M

Thus, the value for [Ag+ ]dilute will be too low

5 0

3 years ago

Classify the following change as physical or chemical: A match lights when struck.

mr_godi [17]

I think the answer is:
B. Chemical Change.

8 0

3 years ago

Define the law of conservation of charge and provide an example.

iren2701 [21]

Answer:

Conservation of Charge is the principle that the total electric charge in an isolated system never changes. The net quantity of electric charge, the amount of positive charge minus the amount of negative charge in the universe, is always conserved.

7 0

3 years ago

Which of the following describes the arrangement of valence electrons in a bond between H and F?

Sloan [31]

C; The Valence electrons spend more time around the atom of F

6 0

3 years ago