Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
9/7is the chance of coming red ball
Answer:
C. it is not a function
Step-by-step explanation:
It fails the horizontal and vertical line test.
To pass the horizontal line test [injective]: must not hit a horizontal line passing through more than once.
To pass the vertical line test [function]: must not hit a vertical line passing through more than once.
Answer:
x=
2
/3
y+2
Step-by-step explanation:
Let's solve for x.
−6x+4y=−12
Step 1: Add -4y to both sides.
−6x+4y+−4y=−12+−4y
−6x=−4y−12
Step 2: Divide both sides by -6.
−6x
/−6
=
−4y−12
/−6
x=
2
/3
y
=x=
2
/3
y+2
<h3><u>
brainliest please?</u></h3>
<u />
Answer A. That is the only one. The rest are not true. Hope his helps! I would appreciate it if you gave me brainliest. Thanks! =D
