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3 years ago

Please help 30 points

Mathematics

1 answer:

KIM [24]3 years ago

4 0

The answer to the equation is 298

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How would you explain to someone the rules of a horizontal translation where we are subtracting from the inputs(within the paren

chubhunter [2.5K]

Answer:

Ok, we know that we can write a horizontal translation as:

y' = f(x - A)

where if A is positive, this moves the graph of f(x) A units to the right.

Why is this?

Ok, let's compare:

y = f(x)

and

y' = f(x - A)

in y, when x = 0 we have f(0).

While to have this same point in y', we need to evaluate in x = A.

f(A - A) = f(0).

Then the value f(0) is now at x = A, this means that the point moved A units to the right.

And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.

5 0

3 years ago

What's is the slope of this line? Need this ASAP

Basile [38]

Answer:

$\displaystyle m=2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Reading a Cartesian Plane

Coordinates (x, y)

Slope Formula: $\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Find points from graph.

Point (0, 3)

Point (1, 5)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Substitute in points [Slope Formula]: $\displaystyle m=\frac{5-3}{1-0}$
[Slope] Subtract: $\displaystyle m=\frac{2}{1}$
[Slope] Divide: $\displaystyle m=2$

5 0

3 years ago

Pls help I will mark brainlist if correct !! :))

andreev551 [17]

You add all fruit and times to 3/8 to find strawberries

3 0

3 years ago

PLEASE HELP ME!!! ANSWER BOTH QUESTIONS & I WILL MARK BRAINLIEST!!!

Nataly [62]

1)b
2)a
Let me know if u want me to show my work

5 0

3 years ago

Verify the identity. 4 csc 2x = 2 csc2x tan x

vlada-n [284]

Step-by-step explanation:

$4csc(2x) = 2csc^2(x) tan(x)$

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

$4 \frac{1}{sin(2x)}$

Also we use identity

sin(2x) = 2 sin(x) cos(x)

$4 \frac{1}{2sin(x)cos(x)}$

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

$2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}$

$2\frac{sin(x)}{sin^2(x)cos(x)}$

$2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}$

We know that sinx/ cosx = tan(x)

Also 1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified

6 0

3 years ago