Answer:
Ok, we know that we can write a horizontal translation as:
y' = f(x - A)
where if A is positive, this moves the graph of f(x) A units to the right.
Why is this?
Ok, let's compare:
y = f(x)
and
y' = f(x - A)
in y, when x = 0 we have f(0).
While to have this same point in y', we need to evaluate in x = A.
f(A - A) = f(0).
Then the value f(0) is now at x = A, this means that the point moved A units to the right.
And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Reading a Cartesian Plane
Slope Formula: 
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Find points from graph.</em>
Point (0, 3)
Point (1, 5)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>
- Substitute in points [Slope Formula]:

- [Slope] Subtract:

- [Slope] Divide:

You add all fruit and times to 3/8 to find strawberries
1)b
2)a
Let me know if u want me to show my work
Step-by-step explanation:

We start with Left hand side
We know that csc(x) = 1/ sin(x)
So csc(2x) is replaced by 1/sin(2x)

Also we use identity
sin(2x) = 2 sin(x) cos(x)

4 divide by 2 is 2
Now we multiply top and bottom by sin(x) because we need tan(x) in our answer



We know that sinx/ cosx = tan(x)
Also 1/ sin(x)= csc(x)
so it becomes 2csc^2(x) tan(x) , Right hand side
Hence verified