4(3h+7)/4+h for h=-2

According to the research, 43% of homes sold in a certain month and year were purchased by first-time buyers. A random sample

vovangra [49]

Answer Do it

Step-by-step explanation 165 divided by 100 =x times 43

4 0

3 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago

Bubble map vocabulary decimal

alisha [4.7K]

Decimal is the dot used after the ones to show parts of one you normally see it in money. 1.50. The . between 1 and 50 is the decimal. Whats in front of the decimal is ones, tens, hundreds, etc and after the decimal is tenths, hundredths, etc.

Hope I helped

6 0

3 years ago

Does the table below represent a function? yes no

Airida [17]

No the table doesn't

5 0

3 years ago

Read 2 more answers

The region R enclosed between the graph of the function y=x^2−4x+5 and the x-axis for 0≤x≤4 is partitioned into four subinterval

Marina CMI [18]

Answer:

9.00 square units

Step-by-step explanation:

The width of the interval is 4 − 0 = 4. Divided by 4 equal subintervals, the width of each subinterval is 4/4 = 1.

The subintervals are:

0 ≤ x ≤ 1

1 ≤ x ≤ 2

2 ≤ x ≤ 3

3 ≤ x ≤ 4

MRAM is midpoint rectangular approximation method. So we use the midpoints of each interval to find the height of the rectangle:

f(0.5) = (0.5)² − 4(0.5) + 5 = 3.25

f(1.5) = (1.5)² − 4(1.5) + 5 = 1.25

f(2.5) = (2.5)² − 4(2.5) + 5 = 1.25

f(3.5) = (3.5)² − 4(3.5) + 5 = 3.25

So the total approximate area is:

A = 3.25 + 1.25 + 1.25 + 3.25

A = 9.00

Graph: desmos.com/calculator/x8dcibqszo

7 0

3 years ago

Read 2 more answers