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snow_tiger [21]
3 years ago
12

I need help using cosine and sine ratios to find the missing side lengths

Mathematics
1 answer:
aniked [119]3 years ago
8 0
I hope this is helpful
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What is the circumference of a circle that has a diameter of 9 in?
postnew [5]

Answer:

The circumference is 28.27in.

8 0
3 years ago
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A fruit bowl contains 3 apples, 2 bananas, and 5 pears. What is the ratio of pears to apples?
algol [13]
The ratio of pears to apples is 5:3
6 0
3 years ago
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The width of a rectangle is 7 inches less than its length. The area of the rectangle is 120 square inches. Solve for the dimensi
pav-90 [236]

Answer:

Length is 15 inches

Width is 8 inches

Step-by-step explanation:

A = L*W

the Width = L-7

120 = L (L-7)

120 = L^2-7L

subtract 120 from each side

0 = L^2 - 7L - 120

(L-15) (L +8 )

so L = 15  inches

and W = 15-7 = 8 inches

check your answer: does 15*8 = 120? yes!

6 0
3 years ago
The table shows a company’s profit based on the number of pounds of food produced.
Bingel [31]

Answer:

$5,300

Step-by-step explanation:

Formulae used,

a=\dfrac{(\sum x^2y\sum xx)-(\sum xy\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}

b=\dfrac{(\sum xy\sum x^2x^2)-(\sum x^2y\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}

c=\dfrac{\sum y}{n}-b\frac{\sum x}{n}-a\frac{\sum x^2}{n}

Where,

\sum xx=\sum x^2-\dfrac{(\sum x)^2}{n}

\sum xy=\sum xy-\dfrac{\sum x\sum y}{n}

\sum xx^2=\sum x^3-\dfrac{\sum x\sum x^2}{n}

\sum x^2y=\sum x^2y-\dfrac{\sum x^2\sum y}{n}

\sum x^2x^2=\sum x^4-\dfrac{(\sum x^2)^2}{n}

Putting the values from the table, we get the best fit line as,

y= -0.0817x^2 + 102.24x - 20421

As we want to calculate the profit at 350 pounds, so putting x=350, we get

y= -0.0817(350)^2 + 102.24(350) - 20421=\$5354.75


5 0
3 years ago
Read 2 more answers
I don’t understand at all
Savatey [412]

Answer and Step-by-step explanation:

The parent function, f(x) = |x|, has no transformations applied to it.

When the number is with the x, it translates the graph horizontally. <->

When the number is outside of the absolute box, it translates the graph vertically. ^ V

When the number is multiply the absolute box on the outside with the x inside, it scales the graph.

So, first lets apply the translations of horizontal and vertical shift.

The graph translated 1 units downwards.

The graph translates 2 units to the right.

g(x) = |x - 2| - 1

We subtract the 2 because that makes it go right, while if we added it would go left.

Now for the scale.

The lines have a slope of \frac{1}{4}, so that is what we are multiplying.

<u> g(x) = </u>\frac{1}{4}<u>|x - 2| - 1</u>

<u></u>

<u>^That is your transformed function.</u>

<u></u>

<u></u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

7 0
2 years ago
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