Let's simplify step-by-step.
<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b2
</span></span></span>There are no like terms.
Answer:
<span>=<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b<span>2</span></span></span></span></span>
Answer:
5 square units.
Step-by-step explanation:
See the attached graph where D, E, F, and G points are plotted.
So, in trapezium DEFG, the parallel sides are GF and DE.
Now, it is clear from the graph that, the length of segment GF = (3 - 1) = 2 units and the length of line segment DE = (3 - 0) = 3 units.
Now, the altitude of the trapezium is GD with length (4 - 2) = 2 units.
Therefore, the area of the trapezium will be given by
![A = \frac{1}{2} \times (GF + DE) \times GD](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%28GF%20%2B%20DE%29%20%5Ctimes%20GD)
⇒
square units. (Answer)
LETITSNOWLETITSNOW
is the hidden message.
The answer is 15
Explanation:
x=3
3(3)+6=15
6(3)-3=15
9(3)-12=15