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Black_prince [1.1K]
3 years ago
8

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l

b), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed? Explain.
Her suitcase already is 47.75 with a 50 lbs limit. There is an extra fee once you go past the limit

PLZ HELP!!
Mathematics
2 answers:
lbvjy [14]3 years ago
7 0
Add some of them or all of them to your sum of 47.75, if either or exceeds the limit then that is what left out.
Rzqust [24]3 years ago
6 0

The total weight of the items is 1.25 + 0.25 + 0.6 + 0.4 = 2.5 lb. 2.5 is 0.25 greater than 2.25, so not all the items can be added. If Li leaves out the extra game, which weighs 0.25 lb, she’d have the greatest possible weight allowed.

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